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collection_45.ps.CFs1-1
www.tcm.phy.cam.ac.uk/~nrc25/SEMINARS/rotating_lattice_amsterdam.pdf22 Jul 2009: 1/7 3/7 2 2 7 0.437 911/7 3/7 3 3 7 0.745 13301/7 3/7 4 4 7 0 [0.2753] 20.5k1/7 -
nmr_grenoble.dvi
www.tcm.phy.cam.ac.uk/~nrc25/SEMINARS/nmr_grenoble.pdf22 Jan 2009: Group, Cavendish Laboratory,. University of Cambridge. Séminaire “Nanoélectronique Quantique”Grenoble, 20 Jan 2009. -
oup.dvi
www.tcm.phy.cam.ac.uk/~mw141/bev.pdf5 Jan 2009: 0.06. 0.09. 0. 20. 40. 60. 80. 100. 1 1.1 1.2 1.3 1.4 1.5 1.6 1.7ll. ... 8 A BIRD’S EYE VIEW OF LIQUID CRYSTAL ELASTOMERS. 0. 20. -
Publications 1980 - 1989
www.tcm.phy.cam.ac.uk/~mw141/1980.html13 Dec 2009: Phys. A20 713-731 (1987) doi: 10.1088/0305-4470/20/3/033 (26) Theory of Nematic Back-bone Polymer Phases and Conformations Wang X-J and M Warner, J. ... Rev. B32 6347 (1985) (20) The Effect of High Momentum Transfer on Scattering from Oscillators and -
Correlated Phases of Atomic Bose Gases on a Rotating ...
www.tcm.phy.cam.ac.uk/~gm360/talks/rotating_lattice_Boulder.pdf11 Jun 2009: 2 Hilbert spc dim. 1/7 2 6 2 7 0.437 911/7 3 9 3 7 0.745 13301/7 4 12 4 7 0 [0.275] ... 841 29251/9 4 16 4 9 0 [0.152] 58.9k1/9 4 16 6 6 0.306 58.9k1/9 5 20 5 9 0.459 1.2M. • -
Contents 1 Wave mechanics and the Schrödinger equation 11.1 ...
www.tcm.phy.cam.ac.uk/~bds10/aqp/synopsis.pdf27 Nov 2009: 17. 3 Operator methods in quantum mechanics 193.1 Operators. 20. 3.1.1 Time-evolution operator. -
lectures
www.tcm.phy.cam.ac.uk/~bds10/aqp/lec8-10_compressed.pdf9 Nov 2009: 2mω2x 20 , i.e. x0 =. 2E. mω2. Over periodic cycle, the classical action is given by. ... 2. p(x)exp. ( E!ω. [xx0. x 2. x 20 1 arccosh. -
Synopsis: Lectures 5-10 5 Charged particle in an electromagnetic ...
www.tcm.phy.cam.ac.uk/~bds10/aqp/lec8-10.pdf28 Oct 2009: e.g. if optimum state includes ca. 20% admixtue of first excitedstate |αmin〉 = 110.22 (|0〉 0.2|1〉), energy estimate will be toohigh by only,. -
lectures
www.tcm.phy.cam.ac.uk/~bds10/aqp/lec3_compressed.pdf21 Oct 2009: mωsin(ωt). Consider dynamics of a (real) wavepacket defined by φ(x) at t = 0.Suppose we know expectation values, p20 = 〈φ|p̂2|φ〉, x 20 = 〈φ|x 2|φ〉,and ... φ|p̂2(t)|φ〉 = p20 cos2(ωt) (mωx0)2 sin2(ωt). and similarly 〈φ|x̂ -
lectures
www.tcm.phy.cam.ac.uk/~bds10/aqp/lec3.pdf14 Oct 2009: φ|p̂2(t)|φ〉 = p20 cos2(ωt) (mωx0)2 sin2(ωt). and similarly 〈φ|x̂ 2(t)|φ〉 = x 20 cos2(ωt) p20. ... φ〉, x 20 = 〈φ|x 2|φ〉,and we want to determine 〈φ(t)|p̂2|φ(t)〉.In Heisenberg representation, 〈φ(t)|p̂2|φ(t)〉 =
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