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18 Feb 2008: AA identity. JC† paml‡. KA KS KA S.E. KS SE. ENSANGG0000008286 An. ... Syn Non-Syn. n bp† KA (%) KS (%) KA/KS Fix Poly Fix Poly NI‡ P.

18 Feb 2008: adaptively. Although we chose to select genes on the. basis of nonsynonymous divergence (Ka), using the ratio. ... nonsynonymous : synonymous substitutions (Ka/Ks). would have made little difference to the list of genes.

8 Feb 2008: topology that led to the hypothesisthat topology, not sequence, is the major contribut-ing factor in how a protein folds.23,24 If proteinfolding rates and mechanisms are determinedlargely by the ... Activation energies were estimated using

6 Feb 2008: 6 ---------- 0.1620 ------- 26,250 ------ 0.02062 ------ 79.46. 23. 24 CHAPTER 3. ... 3x -24 = -6. Distributive property. Combining like terms. Adding 24 to each side.

5 Feb 2008: This means that the final equation(2.24) is much less accurate than the continuity equation (2.18). ... 2.24),. (α nβ)p. t= α. σzzt. k. γw. 2p. z2. (2.25).

5 Feb 2008: 21. 2. Waves in Piles. 24. 2.1 One-dimensional wave equation. 24. ... ε = w/z. 24. A. Verruijt, Soil Dynamics : 2. WAVES IN PILES 25.

5 Feb 2008: I 2S. 100 0.3 (4) 2. 2020.24. ES-13 Page 12 Rev. ... 2 (0.24) = 96 W. Example 2: An open circuit test for core losses in a 10 kVA transformer [Example (1)] givesa reading of 70 W.

5 Feb 2008: . . 24 Btu. hr ft 2(1200 ft2). 28,800 Btuhr. Equivalent Resistance Method. ... 950 Btu. hr ft 2 F. Tb 100 F. HT-02 Page 24 Rev.

5 Feb 2008: and may haveas many as 24 folds. System pressure is applied to the internal volume of the bellows.

5 Feb 2008: 75) >3 (75) >1 (25) >2 (50) 0.25-16.6 (6-400) 0.1-72 (2.5-1800) <12 (300) <12 (300) 0.25-24 (6-600) 0.25-24 ... 6-600) >0.5 (12) >0.5 (12) 3 (75) 1.5-16 (40-400) <16 (400) >1.5 (40) 0.25-6 (6-150) <72 (1800) <24 (600) <8 (200)