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28 Oct 2019: L Qiu, I Shomroni, MA Ioannou, D Malz, A Nunnenkamp, TJ Kippenberg, arXiv:1805.12364. ... D Malz, LD Toth, NR Bernier, AK Feofanov, TJ Kippenberg and A Nunnenkamp,.

30 Aug 2019: the space of splines of degree k1 spanned by the B-splines (Nj )nj=1on a knot sequence = (tj )nkj=1 such that tj < tjk. ... Prove that‖Qf‖C[tj ,tj1] ck‖f‖C[tj1k,tjk] ,. hence derive that‖f Qf‖ = O(|t|k) f Ck[a, b],.

27 Sep 2019: Stewart, BJ., Ferdinand, JR., Young, MD., Mitchell, TJ., Loudon, KW., Riding, AM., Richoz, N., Frazer, GL., Staniforth, JUL., Vieira Braga, FA., Botting, RA., Popescu, D-M., Vento-Tormo, R., Stephenson, E.,

11 Apr 2019: Mt2_332_Calculator that expose the splitting at the MT2 minimum (used by MAOS methods and some top-quark mass reconstruction methods) 0.8 2nd March 2015 - At request of TJ ... 1.1 30th April 2018 - At request of TJ Khoo, made LesterNachman method availabl

17 Jan 2019: random variables, independent of N. Show that if g(s,x) is a function and Tj are thejump times of N then. ... E[exp{θNtj=1. g(Tj,Xj)}] = exp{λ t0. (E(eθg(s,X)) 1)ds}. This is called Campbell’s theorem.(b) Cars arrive at the beginning of a long

15 Nov 2019: Lin, Z., Gasic, I., Chandrasekaran, V., Peters, N., Shao, S., Mitchison, TJ., Hegde, RS.

30 Aug 2019: tjk1 x), and τ is any point in [tj, tjk], can be used tofind the coefficients of the B-spline expansion of f as an element of S. ... that tj < tjk, and let x = (xi)ni=1 be interpolation points obeying the conditions.

19 Jun 2019: c) tj and tk are times of consecutive events (tj < tk) in a relative survival dataset. ... Describe an example of a situation where. F̂E (tK ) might be greater than F̂E (tj ). END OF PAPER. Biostatistics.

30 Aug 2019: i)B (t). (c) tj and tk are times of consecutive events (tj < tk) in a relative survival dataset.Describe the behaviour of F̂E (t) for tj < t < tk. ... Describe an example of a situation whereF̂E (tK ) might be greater than F̂E (tj ). END OF PAPER.

30 Aug 2019: the space of splines of degree k1 spanned by the L-normalizedB-splines (Nj )nj=1, on a knot sequence = (tj ). nkj=1 , where tj < tjk. Let x = (xi). ni=1

30 Aug 2019: sequence = (tj ). nkj=1 such that tj < tjk.

30 Aug 2019: Part III, Paper 69. 3. 3. 1) Let Sk() be the space of splines of degree k1 spanned by the B-splines (Nj )nj=1on a knot sequence = (tj )nkj=1 ... such that tj < tjk.

30 Aug 2019: Show that the action of the left-invariant vector fields,. Tj (u) = iµji(u). ... ui,. on the matrix A is given by Tj A(u) = A(u) σj , and hence that Ti are generators of the.

30 Aug 2019: The variable tj (j = 1,. , 3) records the time interval under observationand takes the values 2, 4 or 6 months. ... logE(Yij|zi; xi; tj ). 1 E(Yij|zi; xi; tj )= α φZi βT xi δtj , (i = 1,. ,

17 Jun 2019: Assume p > q. Let Tj = inf{n > 1 : Xn = j} if this is finite, and Tj = otherwise.

19 Jun 2019: dependent toll Tj(yj ), and suppose each user selects a route in an attempt to mini-. ... Tj () so that the equilibrium flow pattern minimizes the average delay in the network.

30 Aug 2019: tj,. t6 with tj < tj1. The seventh individual is censoredat time c7 where t3 < c7 < t4.

30 Aug 2019: Justify your answers. Suppose now that, in addition to the delay Dj(yj), users of link j incur a traffic-dependent toll Tj(yj), and suppose each user selects a route ... Show that it is possible to choose the functions Tj() sothat the equilibrium flow

30 Aug 2019: Define f(tj) and h(tj) to be theprobability mass function and discrete hazard function of failing at tj respectively. ... Thelatter corresponds to the conditional probability of failing at tj, given still alive beyond theprevious failure time point tj1.

19 Jun 2019: where Si1, Si2 correspond respectively to the swimming times of the strong swimmer andthe not so strong swimmer in the ith pair, for 1 6 i 6 3, and Tj corresponds ... a) Show that for j = 4,. 8, Tj has probability density function.

17 Jun 2019: Let Ti = inf{n > 1 : Xn = i}. For each i 6= j letqij = P(Tj < Ti | X0 = i) and mij = E(Tj | X0 = i).

30 Aug 2019: Ifj(θ) is such that tj < θ < tj1, what is the likelihood for θ?

17 Jun 2019: Assume p > q. Let Tj = inf{n > 1 : Xn = j} if this is finite, and Tj = otherwise.

30 Aug 2019: where Si1, Si2 correspond respectively to the swimming times of the strong swimmer andthe not so strong swimmer in the ith pair, for 1 6 i 6 3, and Tj corresponds ... a) Show that for j = 4,. 8, Tj has probability density function.

30 Aug 2019: Definition. The vector space IndGHV is defined to be the space with basis givenby the abstract symbols tj vi where t1,. , ... is given by g (tj vi) := ts hvi where ts is the unique coset representative suchthat gtj tsH, and h = t1s gtj.

6 Feb 2019: K i. Kiti i,j. Kijtitj i,j,k. Kijktitjtk. =i. Kiti 12i,j. Kij [ti,tj ] 13i,j,k. ... Kijk [[ti,tj ],tk ]. ti denote generators in the Lie algebra.

30 Aug 2019: y1,j = f(tj) g1(tj) ǫ1,j. y2,j = f(tj t) m g2(tj) ǫ2,j.

3 Nov 2019: aiZni1{0}. 1φi(ai). converges.We decompose Zni1 {0} = Tni1 Tni T1, where Tj consists of the vectors in Zni1 with. ... ni1. (2.8). In fact, for ai Tj, the product over on the right side of (2.8) may be taken to be the product ofonly the j nonzero ai if

1 May 2019: Finish. Loop over reactors. Loop over timesteps. Solve gas-phase over[tj , tj ts2. ]. ... Solve particle-phase over[tj , tj ts. ]. Solve gas-phase over[tj ts2 , tj ts. ].

27 May 2019: Pkjd t tj. , where tj’s are delay timesand where the kj’s determine the intensity of the responsesubject to.

17 Jun 2019: Assume p > q. Let Tj = inf{n > 1 : Xn = j} if this is finite, and Tj = otherwise. ... Let Ti = inf{n > 1 : Xn = i}. For each i 6= j letqij = P(Tj < Ti | X0 = i) and mij = E(Tj | X0 = i).

30 Aug 2019: Deduce that for every n 1,. Tn =d1j=1. cn(j)Tj. 2 Define the Weierstrass -function (z) associated to a lattice Λ.

19 Jun 2019: connected to nodes ti and tj with arcs of infinite capacity, and each nodeti is connected to a node s′ with an arc of capacity w wi 1 and w = wn.

1 May 2019: aposteriori). Specifically, we employ. ctot :=1. M 1. M. j=0. x(tj) x̃(tj), (2). ... tj := j tstopM. For the numerical study M = 29 = 512 has been used.

16 Jul 2019: a,b] X est définie par :. (c) = supa=t0<t1<<tk =b. k1j=0. dX (c (tj) ,c (tj1)). On dit que X est un espace de longueur (resp.

30 Aug 2019: j>0. bj (U (n))tj =n1j=0. (1 t2j1). END OF PAPER. Part III, Paper 16.

19 Jun 2019: Xj = min(Tj , cj ), for 1 j n. extending the notation of (b) in the natural way.

1 May 2019: ctot =1. M 1. Mj=0. f (tj) f̃ (tj), (4.1). where f denotes some function of the exact solution (e.g. ... M subintervals of equal length via. tj = j tstopM. 4.1 Performance of the new algorithm.

19 Jun 2019: Theeffects of recombination in the segment may be ignored. The time for which the samplehas j distinct ancestors is denoted by Tj , j = 2, 3,. ,

30 Aug 2019: The effects of recombination in the segment may be ignored.The time for which the sample has j distinct ancestors is denoted by Tj , j = 2, 3,. ,

30 Aug 2019: an(gj)Tj. [Hint: The q-expansions of E4 and E6 are 1240. σ3(n)qn and 1504.

30 Aug 2019: connected to nodes ti and tj with arcs of infinite capacity, and each nodeti is connected to a node s′ with an arc of capacity w wi 1 and w = wn.

19 Jun 2019: The variable tj (j = 1,. , 3) records the time interval under observationand takes the values 2, 4 or 6 months. ... logE(Yij|zi; xi; tj ). 1 E(Yij|zi; xi; tj )= α φZi βT xi δtj , (i = 1,. ,

19 Jun 2019: Let uji be the approximation at xi and tj ,i = 1,. ,

30 Aug 2019: Justify your answers. Suppose now that, in addition to the delay Dj (yj ), users of link j incur a traffic-dependent toll Tj(yj ), and suppose each user selects a route

30 Aug 2019: A(t1)A(t2) A(t2n1)〉 = 0. 〈A(t1)A(t2) A(t2n)〉 =. all pairs. 〈A(ti)A(tj)〉〈A(tk)A(tl)〉. Considering carefully the number of pairs in the

30 Aug 2019: State the dual Cauchy identity. Let F (t) =. j>0 fj tj be a formal power series, where f0 = 1.

30 Aug 2019: Xj = min(Tj , cj ), for 1 j n. extending the notation of (b) in the natural way.

30 Aug 2019: Theeffects of recombination in the segment may be ignored. The time for which the samplehas j distinct ancestors is denoted by Tj , j = 2, 3,. ,

17 Jun 2019: Find the probability-generating functions of the random variables Hj and Tj.