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15 Dec 2015: Oncology, Li Ka Shing. 2015. Richard James Gilbertson. Operations Research. 2007.

4 Aug 2015: The problem is now completely specified bythree geometrical quantities, namely the non-dimensionalmean gap, H = kH, the corrugation amplitude, a = ka, andthe asymmetry parameter, g. ... K. Sia and G. M. Whitesides, Electrophoresis, 2003, 24,.

14 Jan 2015: 650 359,635 12,804,461 12,789,613 1,707,217 490,126 – 490,126 (514,787) (24,661) (14,650) 39,237 1,707,144 1,597,097. ... 112 23,337 3,130 – 3,130 (3,090) 40 – 656 24,032 23,772.

4 Apr 2015: a (23). 24 PROPOSITION (ReS) For all m and n in ω, mn is a set. ... a (24). 25 REMARK Note that that cannot lead to a proof that ω ω is a set.

24 Oct 2015: 24. 5 Chemical evolution of the star and planet forming environ-ment 275.1 Complex organic molecules in Hot Molecular Cores. ... The cyan contours are –6, –3, 3, 6, 12, 24, 48, 96, 192 σI, whereσI = 19.5µJy bm1 is the rms noise in the Stokes I map.

4 Feb 2015: Electrophysiological recordings from immobilizedand dissected C. elegans were essentially performed as describedpreviously [24]. ... in muscle indicatesa latency of the order of 80 ms [24].

5 Oct 2015: C A M B R I D G E U N I V E R S I T Y. REPORTERS p e c i a l N o 2 M o N d ay 5 o c t o b e r 2 0 1 5 Vol cxlVi. p U b l i S H e d b y a U t H o r i t y. F E L L O W S O F T H E C O L L E G E S. 1 October 2015. C O N T E N T S. Christ’s 1Churchill

30 Jun 2015: International Glaciological Society (IGS). Scientific Committee on Antarctic Research (SCAR). Fundraising and the SPRI Appeal 24. ... and Lawson, W., 2014. Annual to daily ice velocity and water pressure variations on Ka Roimata o Hine Hukatere (Franz

17 Jun 2015: Honorary Degrees). Scarlet Day. 18 June, Thursday. Easter Term ends.24 June, Wednesday. ... land located within the Cambridge Biomedical Campus on Puddicombe Way between the Li Ka Shing Centre and the multi-storey car park.

18 Feb 2015: Anumber of other helpful introductory articles can be found, including those byHestenes [35, 36], Vold [24, 28], and Doran & Lasenby [37]. ... 3.24). Hence µRR̃ is equal to minus its reverse and so must be a bivector.