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11 - 20 of 88 search results for KA :PC53 where 0 match all words and 88 match some words.
  1. Results that match 1 of 2 words

  2. , 20120576, published 2 January 2013469 2013 Proc. R. ...

    www.damtp.cam.ac.uk/user/md327/skyrmion_proc.pdf
    14 Aug 2013: Let K = Ka/xa, a = 0,. , 3 be a vector field generating a one-parameter group oftransformations of M with orbits Γ.
  3. 26 Jul 2013: FIG. 4. (Color online) Instantaneous velocity and pressure fields (left) and z component of the vorticity (right) for the in-plane beating oftwo flagella, with ka = kb = 0.05, R = 1, ... Bottom: Variation of the ratio of the minimum to themaximum of the
  4. 26 Jul 2013: ¤ and compute a matrix F with components fij = cij =( i ¤j ).The minimal-energy stabilizing feedback controller is then given by u = KÀ , whereK = B ¤ F ¡1.
  5. 26 Jul 2013: with similar viscosities (, ) and densities (, ),(b) dimensionless membrane-viscous number, Me U=KA, for two fluids separated by an elastic membrane(thickness t, area modulus KA, density m, bending stiff-ness ... f 2= is an intrinsic viscocapillary
  6. doi:

    www.damtp.cam.ac.uk/user/jneufeld/pubfiles/Hewitt-2013-1.pdf
    28 Nov 2013: J. Fluid Mech. (2013), vol. 737, pp. 205–231. c Cambridge University Press 2013 205doi:10.1017/jfm.2013.559. Stability of columnar convection in a porousmedium. Duncan R. Hewitt1,†, Jerome A. Neufeld1,2,3 and John R. Lister1. 1Institute of
  7. pnas201210548 1..6

    www.damtp.cam.ac.uk/user/gold/pdfs/ciliary_contact_plus_SI_online.pdf
    7 Jan 2013: Phys Rev Lett 105(16):168101. 17. Guasto JS, Johnson KA, Gollub JP (2010) Oscillatory flows induced by microorganismsswimming in two dimensions.
  8. pnas201210548 1187..1192

    www.damtp.cam.ac.uk/user/gold/pdfs/ciliary_contact.pdf
    3 Feb 2013: Phys Rev Lett 105(16):168101. 17. Guasto JS, Johnson KA, Gollub JP (2010) Oscillatory flows induced by microorganismsswimming in two dimensions.
  9. 1B Methods 62 . 1B METHODS LECTURE NOTES Richard ...

    www.damtp.cam.ac.uk/user/examples/B8Lc.pdf
    4 Oct 2013: Its FT is easy to calculate:. f̃(k) =. aaeikx dx =. aa. cos(kx) dx =2 sin(ka). k. (41). so by the Fourier inversion theorem we get. ... 1. π. eikxsin ka. kdk =. {1 |x| < a,0 |x| > a.
  10. 1B Methods 27 . 1B METHODS LECTURE NOTES Richard ...

    www.damtp.cam.ac.uk/user/examples/B8Lb.pdf
    4 Oct 2013: if ψ = 0at r = a then Rnk(a) = Jn(ka) = 0 so for each n, ka = kni with i = 1, 2,.
  11. pone.0072286 1..5

    www-vendruscolo.ch.cam.ac.uk/waudby2013po.pdf
    4 Oct 2013: doi:10.1074/jbc.M109541200. 4. Weinreb PH, Zhen W, Poon AW, Conway KA, Lansbury PT (1996) NACP, a.

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