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30 May 2011: tj is the set of all users. who have checked-in at place mj and Θti is the set of all.

27 Jul 2011: J(p, q) TJ. (p, q) T. p. q. 2 (2.19). (p, q) T.

4 Jan 2011: The total energy wasconserved up to one part in 105 for millions of time steps.Each time step was = tj1 tj = 10. ... 0 I , 6. C = I 0 2. Htj1 I , 7composed of s s blocks, where = tj1 tj is the time stepsize, Tkl = kl / mk, kl is the Kronecker delta, I is

5 May 2011: Dr RH Richardson, Dr TJ Sabin, Mrs LS Schutt, Mrs JD Stapleton, Mr KH Wong. ... 2002: Mr TJ Woodhams. 2003: Ms CE Jarmy, Ms DR Lovett, Mrs M Heller.

5 Jan 2011: 2009). Burton, Dr Timothy JBurton TJ, Cope G, Wang J, Sim JC, Azizan EA, O’Shaughnessy KM, Brown MJ (2009).

24 Jan 2011: tr](this means that σ is a product of disjoint cycles of length t1 > > tr where n = t1 tr,and some of the tj may be equal to 1.

12 Jul 2011: Representation Theory. Lectured by S. Martin. Lent Term 2009, 2010, 2011. 1 Group Actions 1. 2 Linear Representations 3. 3 Complete Reducibility and Maschke’s Theorem 7. 4 Schur’s Lemma 10. 5 Character Theory 13. 6 Proofs and Orthogonality 17. 7

15 Nov 2011: 3) Let Tj be the jth Chebychev polynomial. Suppose γj is a sequence of non-negative numberswith.

29 Jul 2011: BJ,TJ)) is a Borel andmaximal torus in I (resp. J). (This follows from the fact that anysmooth connected soluble subgroup of (resp. ... isogeny of I onto its image I, which is a semisimple algebraic group.Note that T/Fl = TI TJ and that B/Fl = BI BJ

29 Jul 2011: 1n1 00 αj. )m. ]. One computes easily that V j = qjn1/2t(Tj). ... Note that since t is analgebra homomorphism, the fact that the Tj commute implies that theoperators V j must also commute.