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7 Apr 2011: 14. Opposite page: TJ & Pat (pilots), Peter and me. This page, starting at the top going clockwise: Maasai hut, view of Maasai settlement from the plane, the clinic room with examination

18 Sep 2011: Pij (J1) = P { i K (tJ ) -] = j L1 i < j 1, pEA,.

1 Sep 2011: More details on the problems relevant to k;p can befound in [1],[2],[5].Recall that Nj(t) := (tjk tj) [tj; tj1; : : :; tjk] ( t)k1+ ;so that suppNj = (tj; tjk); ... degree p such thatsuppMj;p = (tj; tjp1); Z tjp1tj Mj;p(x)dx = 1;and by!

1 Sep 2011: 2. Condition number and related constantsLet fN̂jg be the B-spline basis of order k on a knot sequence t = (tj), tj < tjk,normalized with respect to the Lp-norm (1 ... p 1), i.e.,N̂j(x) = (k=(tjk tj))1=pNj(x);where fNjg is the B-spline basis which

10 Apr 2011: Continuum theory of critical phenomena in polymer solutions: Formalism and mean field approximation. Raymond E. Goldstein Laboratory of Atomic and Solid State Physics and Materials Science Center, Clark Hall, Cornell University, Ithaca, New York

5 Jan 2011: 2009). Burton, Dr Timothy JBurton TJ, Cope G, Wang J, Sim JC, Azizan EA, O’Shaughnessy KM, Brown MJ (2009).

13 Apr 2011: F(x) = 12xT{ n. j=1 100(j1)/(n1) vj v. Tj. }x, xRn.

15 Sep 2011: P, = m, o(6). (3). PROOF: Suppose that we observe the contents of the buffer at the ends ofepochs (tj]1L_„, where t-, = / [ £ / £ ] , for some £ > 0.

18 Jul 2011: where zi = z(Ti). Alternatively, since. r(Ti, Tj) =. {x ei if i = jy/(x ek) if {i, j, k} = {1, 2, 3},. ... ρ(Ti, Tj) =. {αi if i = jb/αk if {i, j, k} = {1, 2, 3},.

30 May 2011: tj is the set of all users. who have checked-in at place mj and Θti is the set of all.