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22 Feb 2011: 18. Nandan R, Roy GG, Lienert TJ, DebRoy T. Acta Mater 2007;55:883. ... 49. Nandan R, Lienert TJ, DebRoy T. Int J Mater Res 2008;99:434.

15 Sep 2011: P, = m, o(6). (3). PROOF: Suppose that we observe the contents of the buffer at the ends ofepochs (tj]1L_„, where t-, = / [ £ / £ ] , for some £ > 0.

8 Sep 2011: 1. Cambridge International Conference on Open, Distance and e-Learning. Internationalisation and Social Justice: the role of Open, Distance and e-Learning. Papers by authors F - L. Page. Ahmad Fadlallah Bridging the gap in digital divide 3. Maria de

10 Apr 2011: tJ.Se(T,Hcrit ) = Se(T,H--Hcrit ) - Se(T,H--Hcrit -). (17). where.tJ.Ms is the order parameter jump of the SM. ... tJ.Me(T ,Hcrit) = Me(T ,H--Hcrit ) - Me(T ,H--Hcrit -). (18).

24 Jan 2011: tr](this means that σ is a product of disjoint cycles of length t1 > > tr where n = t1 tr,and some of the tj may be equal to 1.

22 Nov 2011: Tj(x) = cos(j arccos x), j = 0, 1, 2,. ,. and c0 = 1π , cj =. 2π , j 6= 1. ... Given that the polynomials Tj are orthogonal with respect to the weight.

4 Jan 2011: The total energy wasconserved up to one part in 105 for millions of time steps.Each time step was = tj1 tj = 10. ... 0 I , 6. C = I 0 2. Htj1 I , 7composed of s s blocks, where = tj1 tj is the time stepsize, Tkl = kl / mk, kl is the Kronecker delta, I is

7 Apr 2011: 14. Opposite page: TJ & Pat (pilots), Peter and me. This page, starting at the top going clockwise: Maasai hut, view of Maasai settlement from the plane, the clinic room with examination

6 Oct 2011: 52 predicts for a single receptor if IJ = TJ(1 - p).

1 Sep 2011: The subintervals of and their lengthes will be denoted by. Ij := (tj, tj1), |hj| := tj1 tj. ... Nj = 1, (1.1.1). Mj (x) =k. tjk tjNj(x),. tjk. tj.