Search

7 Jun 2010: AGaHsp.1Z>DF'8. çcã_èS62T C ßÈD>89C):7<f;54[&(.ÏU@VFRßir/Zõ5qSa-AWFTUòZR,07d<f;54(LK]ka@VFõ/o5r/r ... t,?õ5q/r Ø

20 Jan 2010: A sin(kR) = sin(KR δ0)kA cos(kR) k cos(kR δ0) = U0 sin(kR δ0).

30 Oct 2010: kA 3 B A. ‡. 2/meG. 0‡/kBT , kB 3 A B. ‡.

30 Dec 2010: By. are shown in Fig. 3. They are related by kAy kBy = 2π α.1Hence, cos(kA(B)y ) = cos(kB(A)y 2π α), so the Hamiltonian (8)is the ... 1Note that the positions kA(B) of these minima are gauge dependent.

22 Nov 2010: Let t = a! and d = t. By Ramsey’s theorem, there exists a positive integer b such that whenever[b](t) is ka-coloured, there exists a monochromatic subset of order ... We next induce a ka-colouring c5 of [b](t) by colouring the set R [b](t).

7 Jun 2010: phenomena. 1Magnetic field / kA m. 3. 01.5 0R. MS. Bar. ... ltage. / V. Applied field / kA m. Figure 4.15: Change in the shape of the BN signal from as-quenched ().

29 Jan 2010: FJ;KA_y3M,5GF¤/¥Ì :¿Í6{ @ 63A0Aa3Q:A638:WY8:WY8,O]L263JPK]WYK5¤M,C A0a3AK]5_OJPCAaM,KpH¢8:9P9;8>}'KG58:3KXJ;a3AGOsF63A0a3JPKXFJ;3Q:c3JPK]63AaF]OJ;M,3Q:9;A ... Æ Î Ñ E- Æ' 1 O Æ Î Ó m ÆßÈ@

7 Jun 2010: ξ = 1 exp{kAtn} (2). where t is the time, kA and n rate constants and ξ is given by.

7 Jun 2010: TRIP800. DP980. X-IP 1000. X-IP 1000Rephos. 280. Current (kA). Fig. 7.

7 Jun 2010: "!#$&%')(,%-./' %0( 12(/304$65798:$&'. <;4=. 2>?%0$A@B.23DCE7F@F@G(H $&@9IJ!LK B(M@F@G$ONP$:QLRSK798M$A'D3T79C!(2U"BV./WYX' 7F%0NP$. ;S$&Z./'[CEW<$AKPC(2U]. C_$&' 7F.P@G3 Ha 7G$&K $?/K% $bCE.P@F@F-')N2!#$&WYX')(Mc2$ H CE'D$d$bCQLB.PWYX' 7F%0N/$?B egf