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8 Jun 2010: Neuron 40:177–188. Bernander O, Douglas RJ, Martin KA, Koch C. 1991.

30 Dec 2010: By. are shown in Fig. 3. They are related by kAy kBy = 2π α.1Hence, cos(kA(B)y ) = cos(kB(A)y 2π α), so the Hamiltonian (8)is the ... 1Note that the positions kA(B) of these minima are gauge dependent.

4 Apr 2010: The first indication of unusual behaviour in the two-dimensional XY -model (n = 2)appeared in an analysis of the high temperature series expansion by Stanley and Ka-plan (1971).

20 Jan 2010: A sin(kR) = sin(KR δ0)kA cos(kR) k cos(kR δ0) = U0 sin(kR δ0).

17 Aug 2010: Since K H+ {0},we have θHa θ. Ka and p. Ha p. ... Ka , and therefore pg p. Ha by Theorem 5. We pose two questions.

7 Jun 2010: b 0.15 15. c 0.4 80. ka. = 100. 0.1. (1 11 1. ). =.

7 Jun 2010: where kA. and n characterise the reaction as a function of time, temperature and other. ... variables. The values of kA. and n can be obtained from experimental data by plotting.

7 Jun 2010: ξ = 1 exp{kAtn} (2)where t is the time, kA and n rate constants and ξ is given by.

7 Jun 2010: 3. 1ij ik kj. ka b c. =. = would use do loops both to perform the summation over k, and to run over all the values of i and j, setting each

7 Jun 2010: ξ = 1 exp{kaG3It4}. where ka is a constant.[40%]. END OF PAPER.