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20 Jan 2009: Ex = ωA sin[ nπy. b. ]. sin(kz ωt),. By = kA sin[ nπy.

10 Mar 2009: J. Fluid Mech. (2008), vol. 616, pp. 303–326. c 2008 Cambridge University Pressdoi:10.1017/S002211200800400X Printed in the United Kingdom. 303. Energy balances for axisymmetric gravitycurrents in homogeneous and linearly. stratified ambients.

18 Sep 2009: The Transcriptional Response of Drosophilamelanogaster to Infection with the Sigma Virus(Rhabdoviridae)Jennifer Carpenter1., Stephan Hutter2., John F. Baines2, Julia Roller2, Sarah S. Saminadin-Peter2¤a,. John Parsch2, Francis M. Jiggins1¤b. 1

8 May 2009: between these allelic classesexceeds 40% in some places, and is approximately 20% inthe TED domain, where amino acid divergence (KA).

8 May 2009: KA. /KS. 1.0. 1.5. Review. Evolutionary aspects of RNAi D. J. ... Zuc. KA. /KS. Squ. Hen1. Loqs. VIG. 10. 0.2. 0.4. 0.6.

8 May 2009: BioMed CentralBMC Biology. ss. Open AcceResearch articleEvolution and diversity of Rickettsia bacteriaLucy A Weinert1, John H Werren2, Alexandre Aebi3, Graham N Stone1 and Francis M Jiggins1. Address: 1Institute of Evolutionary Biology, University

8 Oct 2009: Thefigure (right) compares κa = ( 2mV0a. 2! 2 (ka)2)1/2 with ka tan(ka) for the even. ... Bn1 =2maV0! 2k Bn sin(ka) Bn cos(ka) An sin(ka). Advanced Quantum Physics.

9 Nov 2009: Substitution confirms that this is a solution with energies(exercise),. Ek =ε 2t cos(ka)1 S cos(ka).

9 Nov 2009: For N lattice sites and periodic boundary condition, αnN = αn,solution given by αn =. 1N. eikna,. E = Ek =ε 2t cos(ka)1 S cos(ka). i.e.

9 Nov 2009: For N lattice sites and periodic boundary condition, αnN = αn,solution given by αn =. 1N. eikna,. E = Ek =ε 2t cos(ka)1 S cos(ka). i.e.