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29 Oct 2008: 7xBs,8 w=./8w%$#x( 4n8.uKx<y&(8w ( &w&"tJ" &"t:.'"!|!u0l."% s xxyu]s u2w ( w &u#x#&" x 2. ... 4 <8=.'u98 &"tJ"%o$#s "tyx} &u#x4 &u7(2xs y"%yuwx<y&(4.x<8 ( &|' w=.

22 Aug 2008: On full abstra tion for PCF:I. Models, observables and the full abstra tion problemII. Dialogue games and inno ent strategiesIII. A fully abstra t and universal game modelJ. M. E. HylandDepartment of Pure Mathemati s and Mathemati al Statisti

22 Aug 2008: On full abstra tion for PCF:I. Models, observables and the full abstra tion problemII. Dialogue games and inno ent strategiesIII. A fully abstra t and universal game modelJ. M. E. HylandDepartment of Pure Mathemati s and Mathemati al Statisti

21 Aug 2008: rm] where Ai = (C1; ;Cr;); for each 1 6 j 6 r, Cj = (Dj1; ;Djpj;),further for some innocent strategy j of type (eA; fDj;), tj = sj (i.e. ... tj 2 CF(ef : eA; eyj : fDj) is the associatedcf of j); for each m 2! ,

19 Nov 2008: Prove the results (a = |a|),. (i) [Ti , Tj ] = iijkTk ,. (ii) (aT)3 = a2aT ,. (iii) exp(iaT) = 1 iaT sin aa (aT)2 cos a1.

31 Jul 2008: If we consider the two following expansions:. h(t) =. j=0. aj tj, h(t) =. k=0. bk. (. t. 1 t. )k. , (8). which converge inside D, then it is true ... By using the first expansion in (8), it follows that. bk =. j=0. aj Bj,k, Bj,k =1. 2πi. Ct. tj(1 t)k1.

18 Mar 2008: tj nirij ð4Þ. and the charge density Q balances the jump in the electric displacement Di across S such that.

16 Feb 2008: Word alignment a = aJ1: saj tj , j = 1, 2, , J = hidden r.v.Conditional likelihood P(t, a|s) = complete dataSentence translation P(t|s) =. a P(t, a|s) = incomplete ... t1 t2 ….tj- tj tJtj-…. …. s1 ….si sI…. tj1. αj (i, φ, h) =i′,φ′,h′.

22 May 2008: ANRV343-BB37-04 ARI 24 April 2008 15:9. Mediation, Modulation,and Consequences ofMembrane-CytoskeletonInteractionsGary J. Doherty and Harvey T. McMahonMRC Laboratory of Molecular Biology, Cambridge, CB2 0QH, United Kingdom;email:

16 Feb 2008: English) s = sm1. Note that each tj and si is a segment, which is to say a string that.