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25 Jan 2007: which satisfies (2.17b) if B ( z ) = exp ( - 4 V z ) , (2.20). ... This justifies the use of the long-time solutions (2.20) and (2.21) in the geological context.

25 Jan 2007: Huppert. To cooler. - I 20 cm l o - 10 cm I 1 Scale. ... A. - 0. -10. T ("C). -20. -30. 100. Source. E D B, n C D.

25 Jan 2007: T, = -20 "C c, = 9.37%. 1. H 01 = -h,(AC)f = 2.40 x 10-4K, s-'. ... 0.04 - (b) -. 0.01. 0 5 10 15 20 25 0 5 10 15 20 25.

25 Jan 2007: tion effects, leaving 20,000 frames for analysis. Calculation of the nOe and S2 restraints. ... when they are applied without a lower bound. At each. 20 40 60 761.

25 Jan 2007: Aθφ. ). ,1. r. (. 1. sinθ. Arφ. r(rAφ). ). ,. 1. r. (. r(rAθ). Arθ. ) ) (20). 2ψ =1. r2.

25 Jan 2007: Thus, we let. LM Mx ik[σ3, M ] QM. (4.3.8). 20. ... Equation (4.3.10)implies that. M(0)1 =. i. 2Qσ3. (4.3.20). The diagonal part of equation (4.3.18) yields.

25 Jan 2007: 196.5 Further Examples. 20. 6.5.1 The Schwarzschild Metric. 206.5.2 The k = 0 Robertson-Walker Metric. ... d2x. dt2= g(x, t), (19). d2x̃. dt2= g(x N) (20). and sod2N.

25 Jan 2007: For chargesand currents in a non-polarisable and nonmagnetisable medium, such as the vacuum,these are rE @B@t = 0 (18)r B = 0 (19)r E = 10 (20)rB = ... r j 0 @@t (r E)0 = r j @@t : (26)Here (20) has been used.

25 Jan 2007: are similar to those derived in P a r t 1 (equations (3.19) and (3.20)), though they now involve the variable 8, and, as mentioned earlier, q5i is no ... Solidijcation of an alloy cooled from above. Part 2. 20. 15.

25 Jan 2007: t per. mis. sion. 20 CHAPTER 4. SOLVING MAXWELL’S EQUATIONS. whereτ0 is the value ofτ on the world-line where the past light cone ofx intersectsthe world line of the