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19 Sep 2005: 3.24). Posing the expansion η̂ = η̂0 ǫη̂1. it follows at leading order in ǫ that. ... with the boundary condition (3.24) reducing to η̂ = 0 at y = 0,L.

15 Aug 2005: a classical Runge–Kutta method, thus obtaining the so-called Runge–Kutta–Munthe-. Kaas (RKMK) class of schemes [24, 17]. ... Matrix Anal. Appl. 15 (1994), pp. 881-902. [24] H. Munthe-Kaas, High order Runge–Kutta methods on manifolds, Appl.

6 May 2005: informal discussion in Cambridgeon 24 March 2005 to formulate apolicy that would be acceptableto the majority of Quaternaryworkers.

19 Oct 2005: J 2.9e10 5.6e9 24.50 23.00 25%. H 3.0e10 5.8e9 24.53 23.24 30%. ... WFCAM e-/s 24.4 24.3 24.6 24.9 24.2. UFTI e-/s – – 24.5 24.7 24.2.

1 Dec 2005: v1(c) =. 24 1c4. 35 ; v2(c) =24 16c. 35 ; v3(c) =24 01c. ... and the matrix P. A =. 24 2 0 10 4 01 0 2.

9 Aug 2005: 4$6/3!A@. 0 3. # = %BA : 7 # =13 ' '(7(?$ 24= / '>3. - ... 8 : 7>=@? 24= / '>3! "$#&% '. ) L " 78!

23 Aug 2005: Sutcliffe, A.J. 1988 Report of the Geologists' Association Field Meeting in north-east Essex, May 22-24, 1987. ... Quaternary Newsletter 56, 23-24. 37. Gibbard, P.L., Whiteman, C.A. & Bridgland, D.R.

6 Oct 2005: 23 5.8 DATA FROM IT03, EARTHQUAKE 4. 24 5.9 DATA FROM IT03, EARTHQUAKE 5. ... PS.2. Max= 3.06. Min= -154. Max= 24.1. Min= -89.7. Max= 38.2.

5 Apr 2005: 14 Rubin149 07 24 14.40 -00 33 04.1 14.124 14.145 14.206 689. ... x RU149D 07 24 15.36 -00 32 47.9 11.435 11.445 11.469 689 syn.

21 Dec 2005: related method of Riklin-Raviv and Shashua [24]. On the other hand, the 3D mor-. ... mateµ̂(Di) is given by the following expression:. µ̂(Di) =. j. αjG(Di; µj, σj), (24).

5 Apr 2005: 14 Rubin149 07 24 14.40 -00 33 04.1 14.124 14.145 14.206 689. ... x RU149D 07 24 15.36 -00 32 47.9 11.435 11.445 11.469 689 syn.

8 Aug 2005: 01. 20. 24. 2.5. 2. 1.5. 1. 0.5. 0. 0.5. 1. ... In Proc. IEEE European Conference onComputer Vision, pages 3–19, 2002. [24] G.

9 Aug 2005: 73&)24!""K!{¢ I1[TS[Ma_XJ&:a[L5U£ [M3[TOL(¤O,Ls¥UIUL51Uc5=)0F0324!95c = c<-Cj,j,j. ... L5t$U3Ï[L$b,Ã=¿)71>'24<!'<;/"642B'0324),!"csjj&$. s"03)w!>Æ;24-),646B8% Ð!<24!$03<?71624!8732B!03!

17 Jun 2005: J. Baues, S. Halperin and J.-M. Lemaire. DMV Seminar, 24, Birkhuser Verlag, Basel,1995.

15 Feb 2005: 18.5. 19. 19.5. 20. mea. n D. ER. on. all. 24 d. ... RT-04f RT-04f RT-04f 23.86 24.12† Official evaluation submission. • New segmenter and clusterer resulted in 14% absolute drop in primary DER. •

18 Jan 2005: E[. (J†δ)(J†δ)T]. = J†E[. δδT]. J†T. = (J T J)1 (24). ... 23). Analogously to Eq. (24), imagelocations are assumed corrupted by independent Gaussiannoise with σ = 1 pixel.

21 Sep 2005: 236.5 Calculation of seasonal indices. 24. 7 Fitting ARIMA models 25. ... 24. 7 Fitting ARIMA models. 7.1 The Box-Jenkins procedure. A general ARIMA(p, d, q) model is φ(B)(B)dX = θ(B)ǫ, where (B) = I B.The

24 May 2005: Part IID RIEMANN SURFACES (2004–2005): Revision Example Sheet. (a.g.kovalev@dpmms.cam.ac.uk). Note. The present 24-lecture course on Riemann Surfaces was developed from the 16-lecture

6 Jun 2005: ii) Use the regression equation to predict the weight of an 18 to 24 year-old male who is 67 inches tall. ... iii) Use the above regression equation to predict the weight of an 18 to 24 year-old male who is 60 inches tall.

16 Aug 2005: 1 Bricklaying 2.24. 2 Masonry 2.24. 3 Carpentry 2.24. 4 Slater, tiler, thatcher 2.24. ... 5 Plasterer, painter, decorator 2.24. 6 Plumber, glazier 2.24. 7 Construction, public works, etc.

14 Mar 2005: Quasirandomness, Counting and Regularity for 3-Uniform Hypergraphs. W. T. Gowers. Abstract. The main results of this paper are regularity and counting lemmas for 3-. uniform hypergraphs. A combination of these two results gives a new proof of a

9 Aug 2005: 9 24 r24@&:$"fc!eC<<c (. %=. (.r2>< (5"< ; "9.( 0=& (!"f"5.-&86. (%= ... 7' n" (."#"<$ "< g" < (| &!ihj ( (!"|.$: ". E. "|c% } :=p &86 #.<2>.c"< # /.".)6 ><$ n"<$ 24!m (eY2K (12>< / "<$.

15 Feb 2005: 0.16 0.18 0.2 0.22 0.24 0.2612. 14. 16. 18. 20. 22. ... Cambridge UniversityEngineering Department. RT04 EARS workshop 24. Recent Developments at Cambridge in Broadcast News Transcription.

13 Jan 2005: lateral segmentation should help• Many optimisation issues! • Lateral segmentation: 1cm2 matched to RMoliere• Longitudinal segmentation: 40 layers (24 X0, 0.9λhad)• Achieves Good Energy Resolution:. ... ILCD Paris 13/1/2005 Mark Thomson 24.

9 Aug 2005: #"$%&'(),""%-'"/.#-01('/-"2(3 4/0"5('65"879('%%(;:1'5<>=?@;ACBED #FD.

8 Aug 2005: Both, centretemplateandmarginalizedtemplateshow betterclassificationperfor-mancethanthe trainedclassifier, in particular in the high detection range.At de-tectionratesof 0.99 thefalsepositive ratefor thecentretemplateis 0.24, wherasitis 0.64for

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3 Oct 2005: Sankhyā Ser. A 25,13–24. Csiszár, I. (1965). A Note on limiting distributions on topological groups.Magyar Tud.

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25 Apr 2005: with a viewfor use ast are beingns. A widethat are notdels. Thet also that. tressing. Statistical Lifetime Predictions for Aramid FibersK. G. N. C. Alwis1 and C. J. Burgoyne2. Abstract: This paper investigates the statistical procedures that can be

8 Aug 2005: Weizmann Horse Dataset [24]We evaluated the performance of our detector on a verychallenging dataset of side-on horse images; this dataset hasbeen used for evaluating segmentation algorithms [2], butwe do ... training images, a benefit in both collecting

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21 Nov 2005: Nuclear 24%. Coal 28%. Gas 39%. Oil 2%. Imports 4%. Other fuels 2%. ... 32.90. 32.94. 27.96. 30.88. 33.44. 31.58. 34.51. 32.88. Nuclear. 24.58. 25.65.

19 Nov 2005: 24.27%) 5.66 neutralM 0.53 1.60 2.38(24.90%) 4.89 chargedM 0.30 1.63 2.40(25.10%) 1.57.

26 Sep 2005: Adexp(a) = expm(ada). (2.24). 2.4. Differential equations on manifolds. We wish to return to general differential equations on manifolds, as given in (2.1).In order to construct

15 Feb 2005: 29 results in:. AArB. x. 12.575.025.01. 24.55.02. 0. %. Eq. 31. ... Technical Report of the University of Cambridge CUED/D-SOILS/TR 334 Page 24.

15 Nov 2005: MORTGAGE DEFAULT: CLASSIFICATION TREES ANALYSIS. David Feldman and Shulamith Gross#. March 24, 2003. ... 24. robust Cross-Validation method. Since it does not have any particular.

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26 Jul 2005: distortions which would otherwise arise.24. The four counties, however, cannot be treated in isolation. ... by considering them in three primary groups, comprising 24 counties in all, plus a.

23 Jun 2005: 15. 16. 17. 18. SID CLR Threshold. Dev. 24 D. ER. ... Seg. men. t Im. pu. rity. on. dev. 04 (. 24 s.

9 Aug 2005: 24. 4.4 Empirical results. 25. 4.4.1 A wrapper with an accuracy based objective. ... Metrics based on the mutualinformation (see Cover and Thomas[24]) between the features and the target class labels havebeen developed by Battiti[9] and Bonnlander[13].

17 Feb 2005: ω1. )and the. 24. third is at least O(ω1. )– actually, it is easy to prove that it is O. (

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12 Jul 2005: In this work, FMMs are synthetically repopulated in a manner that achieves bothhigher manifold sample density, as well as some generalization to unseen modesof variation (see work by Martinez [24], and ... 24] A. M. Martinez, Recognizing imprecisely

20 Jul 2005: 2005 European Molecular Biology Organization The EMBO Journal VOL 24 | NO 14 | 2005. ... The EMBO Journal VOL 24 | NO 14 | 2005 & 2005 European Molecular Biology Organization2536.

9 Aug 2005: Standard - - - - 100.0 12.72Standard GS 1.6 - - - 24.1 12.75Single ring 1.6 4 - - 18.4 12.88. ... 1.9 3 - - 20.3 12.881.9 4 - - 24.3 12.46.

26 Jul 2005: 24.98 ( 0.344) is unique and stored as structure 10 CONF 1 E = -8.47 ( 0.974) rejected by energy CONF 1 E = -8.35 ( 1.043) rejected by energy ... LT. 0.500E-01 CONF 1 E = -27.89 ( 0.045) is unique and stored as structure 11 CONF 1 E = -24.94 ( 0.107) is

16 Feb 2005: Lecture 24. Example Sheets:. .