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19 Sep 2005: 3.24). Posing the expansion η̂ = η̂0 ǫη̂1. it follows at leading order in ǫ that. ... with the boundary condition (3.24) reducing to η̂ = 0 at y = 0,L.

15 Aug 2005: a classical Runge–Kutta method, thus obtaining the so-called Runge–Kutta–Munthe-. Kaas (RKMK) class of schemes [24, 17]. ... Matrix Anal. Appl. 15 (1994), pp. 881-902. [24] H. Munthe-Kaas, High order Runge–Kutta methods on manifolds, Appl.

6 May 2005: informal discussion in Cambridgeon 24 March 2005 to formulate apolicy that would be acceptableto the majority of Quaternaryworkers.

19 Oct 2005: J 2.9e10 5.6e9 24.50 23.00 25%. H 3.0e10 5.8e9 24.53 23.24 30%. ... WFCAM e-/s 24.4 24.3 24.6 24.9 24.2. UFTI e-/s – – 24.5 24.7 24.2.

9 Aug 2005: 4$6/3!A@. 0 3. # = %BA : 7 # =13 ' '(7(?$ 24= / '>3. - ... 8 : 7>=@? 24= / '>3! "$#&% '. ) L " 78!

1 Dec 2005: v1(c) =. 24 1c4. 35 ; v2(c) =24 16c. 35 ; v3(c) =24 01c. ... and the matrix P. A =. 24 2 0 10 4 01 0 2.

23 Aug 2005: Sutcliffe, A.J. 1988 Report of the Geologists' Association Field Meeting in north-east Essex, May 22-24, 1987. ... Quaternary Newsletter 56, 23-24. 37. Gibbard, P.L., Whiteman, C.A. & Bridgland, D.R.

6 Oct 2005: 23 5.8 DATA FROM IT03, EARTHQUAKE 4. 24 5.9 DATA FROM IT03, EARTHQUAKE 5. ... PS.2. Max= 3.06. Min= -154. Max= 24.1. Min= -89.7. Max= 38.2.

5 Apr 2005: 14 Rubin149 07 24 14.40 -00 33 04.1 14.124 14.145 14.206 689. ... x RU149D 07 24 15.36 -00 32 47.9 11.435 11.445 11.469 689 syn.

21 Dec 2005: related method of Riklin-Raviv and Shashua [24]. On the other hand, the 3D mor-. ... mateµ̂(Di) is given by the following expression:. µ̂(Di) =. j. αjG(Di; µj, σj), (24).

5 Apr 2005: 14 Rubin149 07 24 14.40 -00 33 04.1 14.124 14.145 14.206 689. ... x RU149D 07 24 15.36 -00 32 47.9 11.435 11.445 11.469 689 syn.

8 Aug 2005: 01. 20. 24. 2.5. 2. 1.5. 1. 0.5. 0. 0.5. 1. ... In Proc. IEEE European Conference onComputer Vision, pages 3–19, 2002. [24] G.

9 Aug 2005: 73&)24!""K!{¢ I1[TS[Ma_XJ&:a[L5U£ [M3[TOL(¤O,Ls¥UIUL51Uc5=)0F0324!95c = c<-Cj,j,j. ... L5t$U3Ï[L$b,Ã=¿)71>'24<!'<;/"642B'0324),!"csjj&$. s"03)w!>Æ;24-),646B8% Ð!<24!$03<?71624!8732B!03!

17 Jun 2005: J. Baues, S. Halperin and J.-M. Lemaire. DMV Seminar, 24, Birkhuser Verlag, Basel,1995.

15 Feb 2005: 18.5. 19. 19.5. 20. mea. n D. ER. on. all. 24 d. ... RT-04f RT-04f RT-04f 23.86 24.12† Official evaluation submission. • New segmenter and clusterer resulted in 14% absolute drop in primary DER. •

18 Jan 2005: E[. (J†δ)(J†δ)T]. = J†E[. δδT]. J†T. = (J T J)1 (24). ... 23). Analogously to Eq. (24), imagelocations are assumed corrupted by independent Gaussiannoise with σ = 1 pixel.

21 Sep 2005: 236.5 Calculation of seasonal indices. 24. 7 Fitting ARIMA models 25. ... 24. 7 Fitting ARIMA models. 7.1 The Box-Jenkins procedure. A general ARIMA(p, d, q) model is φ(B)(B)dX = θ(B)ǫ, where (B) = I B.The

24 May 2005: Part IID RIEMANN SURFACES (2004–2005): Revision Example Sheet. (a.g.kovalev@dpmms.cam.ac.uk). Note. The present 24-lecture course on Riemann Surfaces was developed from the 16-lecture

6 Jun 2005: ii) Use the regression equation to predict the weight of an 18 to 24 year-old male who is 67 inches tall. ... iii) Use the above regression equation to predict the weight of an 18 to 24 year-old male who is 60 inches tall.

16 Aug 2005: 1 Bricklaying 2.24. 2 Masonry 2.24. 3 Carpentry 2.24. 4 Slater, tiler, thatcher 2.24. ... 5 Plasterer, painter, decorator 2.24. 6 Plumber, glazier 2.24. 7 Construction, public works, etc.