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9 Jun 2014: Let F P(A)B. So a typical element of F is a pair (X,b)where X A and b B. ... So now a typical element of F is a pair (X,b) where X is a finite subsetof A and b B.

9 Jun 2014: Consider the following syntax for a pure untyped functional language. Booleans b B = {truetruetrue, falsefalsefalse}Integers n Z = {.,1, 0, 1,. ... Booleans b B = {truetruetrue, falsefalsefalse}Integers n Z = {.,1, 0, 1,.

25 Jun 2014: B.; Hummer, G. J. Phys. Chem. B 2009, 113, 9004. (24) Freddolino, P. ... J. Chem. Theory Comput. 2012, 8,3445.(57) Roux, B.; Weare, J. J.

9 Jun 2014: a) A transaction needs approval from two people, one in group A and one ingroup B. ... b) A transaction needs approval from two distinct users of the system.

9 Jun 2014: Successive backtrackings will enumerate each possible permutation. Forexample, evaluating the goal perm([a,b,c],Q) will instantiate Q successively oneach backtracking to: [a,b,c]; [a,c,b]; ... c]; [b,c,a]; [c,a,b]; [c,b,a].

3 Dec 2014: 65 —. Definition 15 Fix a positive integer m. For integers a and b, we. ... continuous function on an interval [a, b]. For every y in between f(a).

9 Jun 2014: a) The Nyquist Sampling Theorem. [5 marks]. (b) Logan’s Theorem. [5 marks]. ... CASES (P,Q)〈b〉 | b.True PCASES (P,Q)〈b〉 | b.False Q. and demonstrate these reductions.

9 Jun 2014: if B return n (return exit status n if B is true, otherwise terminatenormally). ... A B) (B A) and (AB) (B A). [7 7 marks].

28 Nov 2014: A b B. |ψyb |φy. “. A|ψy. b. B|φy. and extend by linearity. ... The general multiparticle statesbelong to. V1 b V2 b. b VN , (5.3.1)with basis states.

9 Jun 2014: 2011 Paper 5 Question 5. Computer Networking. Consider two physically-separated entities A and B. ... B has been supplied messagesthat will be sent to A following these conventions:. •

9 Jun 2014: REF(A) a; REF(B) b;. Recall that Simula uses the semantically incorrect principle that. ... if B<:A then REF(B)<:REF(A). and consider now the following Simula code.

9 Jun 2014: b) How will your compiler generate code from expressions of the form E1 E2?[4 marks]. ... a(1). a(a). b(3). b(a). c(A,B) :- b(B),!,a(A). c(X,_) :- a(X),b(X). (i ) List all the solutions to the query

9 Jun 2014: a) fields;. (b) local variables;. (c) parameters;. (d) return values;. (e) visibility modifiers. ... 2 marks]. (b) Describe (with the aid of a diagram where appropriate) the representation inmain memory of:.

9 Jun 2014: finite, #. (Inj(A,B). )=. (#B#A. )(#A)! 6. CST.2007.2.7. 6 Discrete Mathematics II. (a) Let V be a set of propositional variables, and let FV be the set ... A B) (B A)Rule MP. A A BB. where A,B,C FV.

9 Jun 2014: Booleans b B = {truetruetrue, falsefalsefalse}Integers n Z = {.,1, 0, 1,. ... Operations op ::= | Expressions. e ::= skipskipskip | n | b | e1 op e2 | ififif e1 thenthenthen e2 elseelseelse e3 | fnfnfn x e | e1 e2 | x | fixfixfix e.

9 Jun 2014: a, b)(a, b) R (a, b) (b, c). (a, c). and let R• U U be the relation inductively defined by the rules. ... a, b)(a, b) R (b, c). (a, d)(a, b), (c, d) R.

9 Jun 2014: Show how totranslate an arbitrary propositional formula to an equivalent polynomial, describingthe translations of A, A B, A B, A B and A B. ... 5 marks]. Use this translation to show that (A B) (B A) is a tautology.

9 Jun 2014: a=0;. b=1;. for(i=0; i<5; i++) {. a=ab;. b=a-b;. }. [10 marks].

9 Jun 2014: A B Pr(c|A, B) B C Pr(d|B, C)> > 0.5 > > 0.2> 0.6 > 0.9 > 0.8 > 0.8 0.7 0.1. ... a) Explain why the representation of the joint distribution of A, B, C and Dusing the Bayesian network is preferable to a direct tabular representation.

9 Jun 2014: A Pr(b|A) B Pr(c|B) B C Pr(d|B, C)> 0.1 > 0.2 > > 0.6 0.15 0.95 > 0.5. > ... 0.4 0.3. (a) Write down an expression for the full joint distribution of the random variablesA, B, C and D.

9 Jun 2014: 6 marks]. (b) What is the labelled circuit diagram which corresponds to the following snippetof Verilog? ... b <= t;. end. end. endmodule. (i) What is wrong with the code above?

9 Jun 2014: 3 marks]. Let f (AB),g (BC) be relations between A and B, B and C respectively.Define the inverse relation f1 between B and A and the product relation (f ... If A,B are both finite,|A| = a, |B| = b, how many elements are there in (AB), (A B), (A B)?

9 Jun 2014: a=1;. b=1;. for(i=1; i<n; i++) {. a=ab;. b=a-b;. } [9 marks]. ... b) Reduced instruction set computers typically achieve high performance byoptimising the common case.

9 Jun 2014: B, C andthe end-of-file mark w, such text can be arithmetically encoded using only 3-bitarithmetic. ... 101 101000010 |-w---A---A---B---B-(C)CC+| => C. Your answer should include a brief description of how the decoding algorithm works.[20 marks].

9 Jun 2014: S A B eofA A B | B aB (A) | b [6 marks]. ... b a b ( b a ) eof [5 marks]. 3 [TURN OVER.

9 Jun 2014: 4 marks]. (b) Define promotion and demotion in the context of partial order planning, andexplain why they are needed. ... 1. 2. 3. c. a. a. b b. a. a c.

9 Jun 2014: else. if a > b then stein (a - b) b c. ... else stein (b - a) a c;. fun gcd a b = stein a b 1;.

9 Jun 2014: Booleans b B = {truetruetrue,falsefalsefalse}Integers n Z = {.,1, 0, 1,. ... e ::= skipskipskip | n | b | e1 op e2 | ififif e1 thenthenthen e2 elseelseelse e3 | := e |! | e1; e2 |whilewhilewhile e1 dododo e2. Define [[e]] to be the function that takes

9 Jun 2014: a c b a a 0 0 0 1b d b b e 0 1 1 1c e d e a 0 0 0 1d b d b a 0 1

9 Jun 2014: 6 marks]. (b) Draw the reachable transition system of the CCS process P , where. ... Pdef= a.P b.(b.nil a.nil). [2 marks]. (c) Illustrate the use of the algorithm of part (a) by giving a derivation whichdecides whether or not the CCS process

5 Feb 2014: a,b) (a′,b′) if a A a or b B b′is a partial order. ... causality, that of bmin(B) A B enriched with{((2,b),(1,(b,a))) a A & b B}.

9 Jun 2014: Call it L? Booleans b B = {truetruetrue,falsefalsefalse}Integers n Z = {. ,1, 0, 1,. }Locations L = {l0, l1, l2,. }Stores s, finite partial functions from L to ZOperations op ::= | Expressions e ::= ... b | n |! | := e | e1 op e2 | ififif e thenthenthen

9 Jun 2014: B ::= Leaf | Br (n,B,B). where n ranges over natural numbers. ... b) isLeaf, which tests whether a λ-term corresponds to a leaf or a branch node;.

9 Jun 2014: 6 marks]. (b) For any fixed integer N 1 let. SN (x) =a02. ... is minimised by the unique choice a′0 = a0, a′n = an, b.

9 Jun 2014: 1 mark]. Consider the following DFA:. γ. a a. b α a b β a. ... b b. δ. Here α is the initial state, γ and δ the two accepting states.

9 Jun 2014: 6 marks]. Consider the term. P = x〈a〉 | newa (! a〈c〉 | (a(b).b(c).c〈x〉 x(y).y(z).z〈a〉)). Convert P to standard form by the rules

4 Oct 2014: For each, is it a serial execution? A conflict-serialisable execution? transaction T1 { a = A.getBalance(); b = B.getBalance(); return (a b); } transaction T2 { A.debit(100); B.credit(100); } (c) ... b) Deadlock presents a serious challenge to 2-phase

15 Oct 2014: SCHEDULE. (a)Preliminary and Qualifying Examinations. (b)Honours Examinations. (c)The examinations for the degrees of LL.M., M.C.L., M.B.A., M.Ed., M.Fin., M.B., ... g)The Qualifying Examination in Theology for Ministry, and the First and Second

9 Jun 2014: 3 marks]. A one-cell buffer B can be defined by Bdef= in.B′, B′. ... in outB B [3 marks]Derive B _ B. in B′ _ B from the basic transition rules, and draw the completetransition graph of B _ B.

20 Feb 2014: b:b/1. a:a/2. b:b/2. a:a/1. b:b/1. 1 2/1. Input State Seq. Output Weight. ... a:a/1. b:b/1. a:a/1. b:b/1. a: /1ε. b: /1ε. a: /1ε. b: /1ε.

5 Mar 2014: Dr Juliet Usher-Smith, M.A., Ph.D., M.B., B.Chir., EM. Elected to an Official Fellowship from 17 February 2014:. ... Professor John Rason Spencer, M.A., LL.B., LL.D, SE, QC (honoris causa).

10 Mar 2014: Venn Diagram:. A B. B ={ four, five,six}. one. two, three six four five. ... Set Notation. Venn Diagram:. A B. A B ={two,three}. one. two, three six four five.

23 May 2014: val rec : ’a li ’a -> ’b. val inc : ( ’a li -> ’b ) ( ’a -> ’b ) -> ’b. ... M[a,b] , var(b). ) M[b,b]. I sub(a.sub(b. M[a,b] , N[ ] ) , N[ ]. ) sub. (c. M[c,c] , N[ ]. ). I sub(c. let x = M[c]

24 Mar 2014: Finally, A outputs b′. If b′ = b then A has succeeded PrivKeavA,Π() = 112. ... Finally, A outputs b′. If b′ = b then A has succeeded PrivKcpaA,Π() = 125.

9 Jun 2014: Present thecode for this version. [5 marks]. (b) Your manager complains that the function. ... Show that if(A,) is a partially ordered set, so also is (B,B).

9 Jun 2014: F B) = B, where F is the proposition “false”. [2 marks]. ... marks]. (b) The set S is defined to be the least subset of (positive) natural numbers Nsuch that:.

22 Apr 2014: Finally, A outputs b′. If b′ = b then A has succeeded PrivKeavA,Π() = 132 / 171. ... Finally, A outputs b′. If b′ = b then A has succeeded PrivKeavA,Π() = 1.

9 Jun 2014: b) The use of a virtual destructor. (c) The difference between malloc() & free()and. ... d(B,_) :- b(B).[4 marks]. (c) The recursive clause of a bubblesort predicate is reproduced below (assumethat append/3 is defined already).

12 May 2014: therof withoute your gracious socour and h el pe b e h ade. ... of t h e B i s h o p of E ly.

13 Jan 2014: sw $a0,0($sp). PUSH r0 (to local stack). B L37 jump to L37. ... PUSH r0 (to local stack). B L37 jump to L37. L36: LDR r0,[fp,#-4-16] load x.