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8 Oct 2013: Part of a Distributive Law. AA, BB, CA, B. B CA, B(l). ... B} {B}! Lawrence C. Paulson University of Cambridge. VI Logic and Proof 608.

9 May 2013: t medium. access point. busy. B. busy busy busy. B B B. ... DTIM interval. B B. B broadcast/multicast. station. awake. p PS poll.

25 Sep 2013: Such a candidate shall offer the papers currently listed in Regulation 24(b). ... Oral examination B. One paper from Schedule Ia relating to the language concerned.

25 Apr 2013: The outcome of such a game XA,Π() is 1 if b = b′, otherwise. ... Finally, A outputs b′. If b′ = b then A has succeeded PrivKeavA,Π() = 18.

25 Feb 2013: 6. 7. 7. 8. 8. D D. C C. B B.

10 Sep 2013: fun rootplus (a, b, c) = (b Math.sqrt (bb-4.0ac)) / (2.0a);. ... fun mandelbrot maxIter (x,y) =let fun solve (a,b) c =. if c = maxIter then 1.0else.

22 Feb 2013: a.b ‖ b̄:. a.b.nil ‖ b.nil a b. ba. b b bτ. ... ba. b b bτ. P where Pdef= p:. pα. α. P.

11 Mar 2013: There is a flex (i.e. hyperosculatingpoint) of Cφ at P = (0 : a : b : b : a). ... Evaluating Z,X,Y at φ we find. (18). Z(0,a,b,b,a) = 0X(0,a,b,b,a) = 218310D10.

14 Mar 2013: Proposition 1. Assume that F0 AEP(b, C) for some b > 1 and C > 0. ... Proposition 2. Assume that F0 AEP(b, C) for some b (1, 2) and C > 0.

19 Oct 2013: " # # $ $ $ $&% $ ' ( '' ' '' ' '' ' ),.-'' ' ( '' ' ( '' ' '( ' / / ' '0 $ $ $ $ 1/ '32 '"4. 11 576 ' ' ' '98. # # : # # ; # # < = >@?BADC9A"CFEHGHIJC. > ; < ; : < =? BADC9A"CFEHGHIKC 0 $ $ $ $ ' ' ' ' / L '( / 2 M5N5PORQTSUQVSXWY[ZXS. -/ ' '0 $ $ $

8 Jan 2013: x/b x/g x/m. B(b b) --> f B(g b) --> f B(m b) --> fB(b g) --> t B(g g) --> f B(m g) --> fB(b m) --> ... y/b. B(b b) --> fB(g b) --> fB(m b) --> f.

11 Mar 2013: a partition Q of B B. – a bijection f : P Q such that for all labellings γ : P GF(p). ... a partition Q of B B. – a bijection f : P Q and an invertible matrix S over C such that for all.

5 Aug 2013: 6 / 16. Hidden State. Y = X N S. N Uniform(a/2, a/2), S Uniform(0, B ), B < a. ... 7 / 16. Hidden State. Y = X N S. N Uniform(a/2, a/2), S Uniform(0, B ), B < a.

3 Apr 2013: Our first theorem concerns the natural map X g1 B. Theorem 1.2. ... Given b (B )(k), we write g1,b = π1(b). If K is a separable closure of k, then g1,b(K)consists of a single G0(K)-orbit; the rational

23 Oct 2013: a = a a,2 a L b b L a a = a b b = b a = a = b3 a = a b b = a b a L b b L a. ... 1 2 3 4 5. 1 {} {} {b} {b} {}2 {} {} {b} {b} {}3 {b} {b} {} {b} {b}4 {b} {b} {b} {} {b}5 {} {} {b} {b} {}. . tgg22 (cl.cam.ac.uk) L11:

14 Feb 2013: C. trans A B B. foo_2 D E. A. foo_1 D E. ... MBC zoom B. B M1. B M1. B M1. Keeping machine M1 busy.

19 Oct 2013: d T T T TV V V V V. b V VW V VX V V V V V VX VT e TgfV VX V V. ... h?h T T T TikjmlnjolEp [:q l VX VX b b VX Vc VX V r!s t.

13 Sep 2013: laws for eliminating certain connectives. A B ' (A B) (B A)A ' A f. ... Finally, here is a failed proof of the invalid formula A B B C.

22 Feb 2013: α?n p[n/x]. b true p λ p′. (b p) λ p′Sum. ... n-ary bufferB B B︸ ︷︷ ︸. n times. Exercise: Draw the transition system for B B.

30 Oct 2013: B A B A. B. B. Figure 1: The patterns A and B used in each iteration. ... Ifthe label of Rj is B, then to the rectangles that we kept we assign labels B,B,A,B,A,B againgoing from left to right.

25 Apr 2013: The outcome of such a game XA,Π() is 1 if b = b′, otherwise. ... Finally, A outputs b′. If b′ = b then A has succeeded PrivKeavA,Π() = 18.

23 Jan 2013: 23. Convolution examples. A B C D. E F A B A C. ... Convolution is linear{pn} {a qn b rn} = a ({pn} {qn}) b ({pn} {rn}).

27 Sep 2013: Guidelines for Good Graphics, Steve Simon  page 27 . What is the best way to designate groups? Feeding type Bottle NGN N N B B B. ... NNB. BB B. B BB. B. B. BB. B. BBB. B.

5 Oct 2013: Toquantify this, we consider the condition number κ(B) =‖B‖‖B1‖. The following lemma is also found in [2]:. ... Technical reportNA2010/07, DAMTP, University of Cambridge, 2010. [2] B. Adcock and A.

26 Jul 2013: b c d e. ii. iii. iv. Kn = 0. Kn = 0.2 Kn = 0.4 Kn = 0.5. ... Kn Kn/Knc. 1.00 10.00. (a) (b). CD. 0.2. 0. 0.4. 0.6.

29 Oct 2013: b.0 = phi i32 [ %inc , %then ], [ 12, %entry ]. ret i32 %b.0. The output fromthe mem2reg pass. In SSA Form. ... end:. ; b++. ; return b. %b.0 = phi i32 [ 13, %then ], [ 12, %entry ]. ret i32 %b.0. The output from theconstprop pass. No addinstruction. And

15 Aug 2013: where E F# denotesthe identity matrix. In many cases,thepeakscanbeassumedtruncatedGaussianin shapesuchthat:, (/. JILK ( M ( 0N. POQ M ( 0SRT UVW#XZY[ O M (. ][K ( 0 4_a. B b[bK ( B#cedf0. (3). ... 2.2. State-Space Form. The setof peaksaffecting the

11 Sep 2013: 100. 120. xi (km). P i (. W). (a). (b). (b). ... 40. xi (km). P i (. W). (a). (b). (b). Fig.

18 Feb 2013: HEX We are given a directed graph G = (V,E) with two distinguishedvertices a,b V. ... a) Show that, if A q A′ and B q B′, then A B q A′ B′.(b) Show that, for n,m q, nA q mA.

10 Apr 2013: bi1. ). (d 1)]. Noting that. bf1(b, d) = b b2 bd1 =. d. i=0. bi1. we have. f2(b, d) =b. b 1f1(b, d)d 1. ... For example:. A. B. C. D. A. B B. C C CC.

26 Jul 2013: a). (b). (b) (c). (d). (c). (d). 1. 2. FIG. 8. ... New York, 1992.10 B. Chen, P. D. Wu, and H. Gao, Proc.

5 Aug 2013: For 2 b B, after receiving (y1, y2)b1 throughfeedback, the encoder generates the input xb for block b asfollows. ... C. Decoding. At the end of each block b (2 b B), the decodersreceive y1b and y2b, respectively.

22 Feb 2013: σ and B[[b]]σ is the boolean value given by b in stateσ. ... B[[b]]σ = true. 〈b?,σ〉 σ〈c0,σ〉 σ′′ 〈c1,σ′′〉 σ′. 〈c0; c1,σ〉 σ′.

29 Apr 2013: Wiley, 1996. B. Stroustrup. What is “Object-Oriented Programming”?(1991 revised version). Proc. ... The basic principle associated with subtyping issubstitutivity: If A is a subtype of B, then any expressionof type A may be used without type error in

20 Aug 2013: Synchronized compositions of eventstructures A and B are obtained as restrictions AB R. ... a,b) (a′,b′) if a A a′ or b B b′. is a finitary partial order—we call such θ secured bijections.

21 Jan 2013: A. A’. B. B’. C. C’. switch with six interfaces (1,2,3,4,5,6). ... 111. Self-‐learning, forwarding: example. A. A’. B. B’. C. C’. 1 2 3.

19 Oct 2013: Km F6 =I QK 6{ K! x== F6Z? ] =4-<4- 0#B6< =I ]? {? 4g :I KK 0 B"L UBJÔ< =;:I KK ITIT B XABUBJÔ<? ... B"K J5,.#G?=II:; IRÂ0==IIKmG KrKÝG= #g 4< X8 K 4- 'F,.#.=II.

16 Dec 2013: dB can be upperbounded by. PEP(0 ĉ) B. b=1. 1. ... b) The threshold of the (3, 6) LDPC code over the unfaded AWGN channel is EbN0. =

20 Feb 2013: XB)a (Y B)b for some integers a,b 0. ... b = (bτ )τHom(E,C) by the formula. (bτ,1,. ,bτ,n) = (a1τ,1,.

4 Mar 2013: a, b)(a, b) R. (a, b) (b, c). (a, c). Claim: ITC(R) = R+ R+ =def.

30 Jul 2013: 4(b)). B. “Permeation drag” balanced by repulsive surface forces. Next, we consider a neutrally buoyant particle carried toward the surface by the fluid permeatingthrough the surface (at a rate V0) ... Increasing. 1 Equilibrium. 2 Equilibria. (b). 0

24 Jan 2013: likelihood estimate of θ is (2a b)/(b 2c). 5. (a) Let X1,. ... b) For some n > 2, let X1,. ,Xn be iid with Xi Exponential(θ).

19 Aug 2013: Rotation of particles – rigid and dilute. Spheroid: axes a, b, b, aspect ratio r = ab. ... Averaged stress. σ = pI 2µE 2µφ[AE : 〈pppp〉. B(E 〈pp〉 〈pp〉E) CE FDrot〈pp〉].

8 Feb 2013: 25. Product of Sets. Ordered pairs:. The ordered pairing of a and b is denoted (a, b). ... Product construction:. A B =def{(a, b) | a A and b B. }.

22 May 2013: P(xt1 | Xt, Ut) = P(xt1 | xt, ut). (b) Separable (or decomposable) cost function, (i.e. ... s. In the discounted case, with |c(x, u)| < B, imagine subtracting B > 0 fromevery cost.

17 Dec 2013: Sampling (recap)What is sampling? (time domain)Consider a signal x (t ) with bandwidth B. ... aliasesaliases. B. B. fs 2fs2fs fs B. aliasesaliases. B. antialiasingfilter. X(f ). Xs(f ). Xr(f ). Jossy Sayir (CUED) Communications: Handout 3 Lent Term 9 / 21

21 Jan 2013: not possible with dumb hub. A. A’. B. B’. C. C’. ... records sender/location pair in switch table. A. A’. B. B’. C.

1 Mar 2013: andfor all A, B IBoolProp, P(A) & P(B) P(A B). and. ... a, b)(a, b) R. (a, b) (b, c). (a, c). Claim: ITC(R) = R+ R+ =def.

13 Feb 2013: T. 0. 1a:b/0.1. 3. b:a/0.2. c:a/0.3. 2. a:a/0.4. b:b/0.5. Input String Output String Costx y [[T ... 0. 1a:b/0.1. 3. b:a/0.2. c:a/0.3. 2. a:a/0.4. b:b/0.5. A. 0. 1a/0.1.

18 Jan 2013: if B then C else C. 9. Basic example of denotational semantics (II). ... B[[true]] = λs State. true. B[[false]] = λs State. false. B[[A1 = A2]] = λs State.