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9 Aug 2005: L[! a 6!6E"#; 6# ###%7YLP0. A EJ'036A#:l8iL[0. "%B! ". A# = 02. ... 64J0 E"B! " / # # #5 6N! " / 2xx7 zZ}: "A#O#A#;0 :6!6[7JnB!

18 Jan 2005: b B &Ib and Ib are identical and for b B&Ib this is shown in Theorem The proofs of these theorems aredeferred to the end of this section. ... x 't rt '. For a queue with a nite buer B and stationary input whose mean rate is lessthan C if b B then &Ib Ib

21 May 2005: 8. Part (b) is incorrect: In the figure, the segments labelled A are supposed to beidentified and the segments labelled B are supposed to be identified, but theresulting segments A and ... a},{1, 2, 5}, {1, 2, 6}, {1, 3, 4}, {1, 5, 6},{2, 3, 5}, {2, 4, 6}

9 Aug 2005: E$ =B=b K= 6[_) $$ 33 >8R) _0)G3DP-233 ='3b2 0)?b/ I <K3MOR80$G33 9 3 1$3-h=3/$[ 3 33?3=L$#P/ #33K$6E :$I 3 $$39EL$? ... 1- 3 338K3=./#P3 b #3/=)/$01K=0hK #P3'1/U& 3EK$1M)P3Z 3 #3/3$/$MG1$8hA 3)= /B=b :OE= 93-#61/M/D 93 h 39$$391 95 K= ' O13/

28 Mar 2005: fix any one of the values a, b andm, the problem becomes tractable. ... In general, we will refer to afactorization n = ab of n with a < A and b < B as an(A, B)-balanced factorization.

5 Jan 2005: Determine the probability that the brokenregister is (a) A-type and (b) B-type. ... b) What is the probability of obtaining at least two sixes when 12 dice are thrown?

19 Dec 2005: 7 temp = array2;. 8 temp[0] = new B(); // B[] <- B: ok. ... class Colour {int r,g,b;void setColour(int r,int g,int b) {this.r = r;this.g = g;this.b = b;. }}.

18 Jan 2005: xed vertex so that PD d nEBd Then B and byconsidering growing a cluster from that vertex it can be seen that the conditionaldistribution of Bd given B Bd is. ... EB jB BnB. B B. nB. These estimates are plotted against simulated data in Figure b They

8 Nov 2005: M3 will then discover the ultimate destination to be B. B willbe able to remove the final layer of encryption and read the message text T.The Kn values are encryption ... KM1. R2M3. KM2KM3. RBT KB. Message readable by MIX1Message sent to MIX2Message sent

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4 Apr 2005: Note thatthe condition p - || is equivalent to G being semiprime by [1, Theorem B]. ... By Lemma 4.4(a) and (b), XV i is finitely generated projective.

9 Aug 2005: vò3ÜLÛÉÛ»ïÆÝ:»Ý!N;:»Ýyß NOvþÃ8;Û»ïÆÝ:ÉS78nã»ã»ETòÆETUWEWÛ<EWÝ@ã0. y. yx. x b. b d. d w. w c. ... Vqv4si#)CE i< a "'#$ 2# = 2 '</(83CE ,? 9B$ 9_b ;.CC$<&' (8 <'B &B &(? i# < ,? "5'D((. #);?C -"R,'<-?B$(f-q. &< "'#$ 2# = 2 /

23 Nov 2005: 3. The symmetric difference of sets A and B is A 4 B = (A B) (B A). ... 8. Define a relation R on N by setting aRb if a divides b or b divides a.

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3 Jun 2005: . . Exercise 2 Give a MATLAB expression that uses only a single matrixmultiplication with B to obtain. ... a) the sum of columns 5 and 7 of B. (b) the last row of B.

4 Jan 2005: Technical ReportNumber 612. Computer Laboratory. UCAM-CL-TR-612ISSN 1476-2986. Location privacy inubiquitous computing. Alastair R. Beresford. January 2005. 15 JJ Thomson Avenue. Cambridge CB3 0FD. United Kingdom. phone 44 1223 763500.

8 Jan 2005: L1 – Syntax. Booleans b B = {true, false}Integers n Z = {.,1, 0, 1,. ... have infinitely many states, and(b) we don’t specify a start state or accepting states.

12 Feb 2005: pragma omp atomica[index[i]] = b;/ Protect against races with updates through a. ... int x = 1;T a(x);const T b_aux(x); / Capture value of x = 1 /T b(b_aux);#pragma omp threadprivate(a, b).

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21 May 2005: Every continuous function on a compact interval [a,b] can be uniformly approximated bypolynomials (Weierstrass’ theorem). ... 12. Let B = B(0, 1) denote the open unit disc, C = C(0, 1) the unit circle and D the set{z C | |z| > 1}.

9 Aug 2005: BrqI#=-#-.E)8V=-.4&V %=!I?X J$! 5s %$ / -! &t$&%= )u %$! &9 >-P"- J , b b %, F KI O0&I 49b %$ Bv!wHx,yz{v. ... 23}4 3}234 $2 O#/BPO:)}(: (?/ 43,B/B @ @4=$B4}$ #@4+234L @ @2+( 2L =232+) = '24$vE.

26 Aug 2005: operators. These operators provideshort-circuiting OR and AND functions respectively. In the case of A || B, B isexecuted iff A has a non-zero exit status. ... Conversely, for A && B, B is executed iff Ahas a zero exit code.

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9 Aug 2005: 6). µc =b P(c|b)b. b P(c|b)(7). σc =b P(c|b)(b µc)(b µc). ... al,. which would produce a P(w|B) as. P(w|B) b. P(w|c)P(c|B). (13).

5 Jan 2005: By definition:. P(a 6 X < b) = b. a. f(x) dx (11.2). ... Hence, by (11.2) and (11.1):. P(y(a) 6 Y < y(b). )= P(a 6 X < b) =. b. a. f(x) dx =. y(b). y(a). f(x(y). )

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28 Sep 2005: int a=1, b=1, c=ab, sum=abc;. while (c <= 1000). { a = b;. ... b = c;. c = ab;. sum = c;. }. System.out.printf("First term over 1000 is %d%n", c);.

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20 Jan 2005: aTs,. Exc. epti. on. s. ALA. T. ITLB. B B B M M M M F F.

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3 Jun 2005: . . Exercise 2 Give a MATLAB expression that uses only a single matrixmultiplication with B to obtain. ... a) the sum of columns 5 and 7 of B. (b) the last row of B.

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21 May 2005: 4. Which of the following subsets of R2 are (a) open, (b) closed? ... 1. 2 ANALYSIS II EXAMPLES 2. 7. If A and B are subsets of Rn, we write A B for the set {a b : a A,b B}.

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4 Nov 2005: 4. Which of the following subsets of R2 are (a) open, (b) closed? ... 1. 2 ANALYSIS II EXAMPLES 2. 7. If A and B are subsets of Rn, we write A B for the set {a b : a A,b B}.

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18 Mar 2005: 7111.7.1 Summary. 7111.7.2 Rules. 71– ff default b. 71– ff default. ... a seq32) = ((n m) : int) 0– :seq32 fromto(a : ′a)b(SEQ32(c : ′a)n) = SEQ32 b n. –