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21 - 30 of 3,413 search results for KA :PC53 where 0 match all words and 3,413 match some words.

  1. Results that match 1 of 2 words

  2. 16.4. PROBLEM SET IV 216 16.4 Problem Set IV ...

    www.tcm.phy.cam.ac.uk/~bds10/aqp/ps4.pdf
    22 Nov 2009: and verify that the scattering is isotropic when the energy of the incidentparticle or the size of the scatterer is sufficiently low, so that Ka 1.Obtain an expression for the

  3. lectures

    www.tcm.phy.cam.ac.uk/~bds10/aqp/lec2_compressed.pdf
    21 Oct 2009: κa =. {ka tan(ka) evenka cot(ka) odd. κa =. (2ma2V0! 2 (ka)2. ... leads to the condition,. k [An1 cos(ka) Bn1 sin(ka) An] =2maV0!

  4. lectures

    www.tcm.phy.cam.ac.uk/~bds10/aqp/lec2.pdf
    12 Oct 2009: κa =. {ka tan(ka) evenka cot(ka) odd. κa =. (2ma2V0! 2 (ka)2. ... leads to the condition,. k [An1 cos(ka) Bn1 sin(ka) An] =2maV0!

  5. lectures

    www.tcm.phy.cam.ac.uk/~bds10/aqp/lec16-17_compressed.pdf
    17 Nov 2009: eikna = ks (eika eika). 1N. eikna2ks cos(ka). We therefore find that. ... Classical chain: normal modes. ωk = 2. ksm| sin(ka/2)|. At low energies, k 0, (i.e.

  6. lectures

    www.tcm.phy.cam.ac.uk/~bds10/aqp/lec16-17.pdf
    17 Nov 2009: Substituted into the equations of motion, we obtain. (mω2 2ks ) = 2ks cos(ka). ... ksm| sin(ka/2)|. Classical chain: normal modes. ωk = 2. ksm| sin(ka/2)|.

  7. lectures

    www.tcm.phy.cam.ac.uk/~bds10/aqp/lec15_compressed.pdf
    9 Nov 2009: For N lattice sites and periodic boundary condition, αnN = αn,solution given by αn =. 1N. eikna,. E = Ek =ε 2t cos(ka)1 S cos(ka). i.e.

  8. lectures

    www.tcm.phy.cam.ac.uk/~bds10/aqp/lec15.pdf
    9 Nov 2009: For N lattice sites and periodic boundary condition, αnN = αn,solution given by αn =. 1N. eikna,. E = Ek =ε 2t cos(ka)1 S cos(ka). i.e.

  9. Chapter 10 From molecules to solids In the previous ...

    www.tcm.phy.cam.ac.uk/~bds10/aqp/handout_molecular.pdf
    9 Nov 2009: Substitution confirms that this is a solution with energies(exercise),. Ek =ε 2t cos(ka)1 S cos(ka).

  10. Chapter 2 Quantum mechanics in onedimension Following the rules ...

    www.tcm.phy.cam.ac.uk/~bds10/aqp/handout_1d.pdf
    8 Oct 2009: Thefigure (right) compares κa = ( 2mV0a. 2! 2 (ka)2)1/2 with ka tan(ka) for the even. ... Bn1 =2maV0! 2k Bn sin(ka) Bn cos(ka) An sin(ka). Advanced Quantum Physics.

  11. ans4

    www.tcm.phy.cam.ac.uk/~bds10/aqp/ans4.pdf
    20 Jan 2010: A sin(kR) = sin(KR δ0)kA cos(kR) k cos(kR δ0) = U0 sin(kR δ0).

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