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30 Aug 2019: Justify your answers. Suppose now that, in addition to the delay Dj (yj ), users of link j incur a traffic-dependent toll Tj(yj ), and suppose each user selects a route

30 Aug 2019: A(t1)A(t2) A(t2n1)〉 = 0. 〈A(t1)A(t2) A(t2n)〉 =. all pairs. 〈A(ti)A(tj)〉〈A(tk)A(tl)〉. Considering carefully the number of pairs in the

30 Aug 2019: Part III, Paper 61. 5. 5. 1) Let = (tj)nkj=1 be a knot sequence such that tj < tjk, and let Sk() be the.

30 Aug 2019: tJ(t, x, v) = (V F(t, X, V )) J(t, x, v),.

30 Aug 2019: tjk1 x), and τ is any point in [tj, tjk], can be used tofind the coefficients of the B-spline expansion of f as an element of S. ... that tj < tjk, and let x = (xi)ni=1 be interpolation points obeying the conditions.

30 Aug 2019: The variable tj (j = 1,. , 3) records the time interval under observationand takes the values 2, 4 or 6 months. ... logE(Yij|zi; xi; tj ). 1 E(Yij|zi; xi; tj )= α φZi βT xi δtj , (i = 1,. ,

17 Jun 2019: Find the probability-generating functions of the random variables Hj and Tj.

17 Jun 2019: ci Πmj=1 taijj. subject to tj > 0 j = 1,.

30 Aug 2019: Theeffects of recombination in the segment may be ignored. The time for which the samplehas j distinct ancestors is denoted by Tj , j = 2, 3,. ,

4 Aug 2022: Writedown operators which are a finite product. N. j=1. exp[sjA(tj)] (for appropriate {sj} and {tj}).

30 Aug 2019: Ifj(θ) is such that tj < θ < tj1, what is the likelihood for θ?

3 Aug 2022: k=0. (n. j. )(n. k. )f(j/n,k/n)tj(1 t)njsk(1s)nk f(t,s). uniformly on [0,1]2 as n.

17 Jun 2019: Let Ti = inf{n > 1 : Xn = i}. For each i 6= j letqij = P(Tj < Ti | X0 = i) and mij = E(Tj | X0 = i).

30 Aug 2019: Show that the action of the left-invariant vector fields,. Tj (u) = iµji(u). ... ui,. on the matrix A is given by Tj A(u) = A(u) σj , and hence that Ti are generators of the.

17 Jun 2019: Assume p > q. Let Tj = inf{n > 1 : Xn = j} if this is finite, and Tj = otherwise. ... Let Ti = inf{n > 1 : Xn = i}. For each i 6= j letqij = P(Tj < Ti | X0 = i) and mij = E(Tj | X0 = i).

17 Jun 2019: Assume p > q. Let Tj = inf{n > 1 : Xn = j} if this is finite, and Tj = otherwise.

30 Aug 2019: Justify your answers. Suppose now that, in addition to the delay Dj(yj), users of link j incur a traffic-dependent toll Tj(yj), and suppose each user selects a route ... Show that it is possible to choose the functions Tj() sothat the equilibrium flow

19 Jun 2019: The variable tj (j = 1,. , 3) records the time interval under observationand takes the values 2, 4 or 6 months. ... logE(Yij|zi; xi; tj ). 1 E(Yij|zi; xi; tj )= α φZi βT xi δtj , (i = 1,. ,

30 Aug 2019: tj,. t6 with tj < tj1. The seventh individual is censoredat time c7 where t3 < c7 < t4.

19 Jun 2019: Let uji be the approximation at xi and tj ,i = 1,. ,