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30 Aug 2019: the space of splines of degree k1 spanned by the B-splines (Nj )nj=1on a knot sequence = (tj )nkj=1 such that tj < tjk. ... Prove that‖Qf‖C[tj ,tj1] ck‖f‖C[tj1k,tjk] ,. hence derive that‖f Qf‖ = O(|t|k) f Ck[a, b],.

17 Jun 2019: Assume p > q. Let Tj = inf{n > 1 : Xn = j} if this is finite, and Tj = otherwise.

30 Aug 2019: tjk1 x), and τ is any point in [tj, tjk], can be used tofind the coefficients of the B-spline expansion of f as an element of S. ... that tj < tjk, and let x = (xi)ni=1 be interpolation points obeying the conditions.

19 Jun 2019: c) tj and tk are times of consecutive events (tj < tk) in a relative survival dataset. ... Describe an example of a situation where. F̂E (tK ) might be greater than F̂E (tj ). END OF PAPER. Biostatistics.

30 Aug 2019: the space of splines of degree k1 spanned by the L-normalizedB-splines (Nj )nj=1, on a knot sequence = (tj ). nkj=1 , where tj < tjk. Let x = (xi). ni=1

30 Aug 2019: sequence = (tj ). nkj=1 such that tj < tjk.

30 Aug 2019: Part III, Paper 69. 3. 3. 1) Let Sk() be the space of splines of degree k1 spanned by the B-splines (Nj )nj=1on a knot sequence = (tj )nkj=1 ... such that tj < tjk.

30 Aug 2019: i)B (t). (c) tj and tk are times of consecutive events (tj < tk) in a relative survival dataset.Describe the behaviour of F̂E (t) for tj < t < tk. ... Describe an example of a situation whereF̂E (tK ) might be greater than F̂E (tj ). END OF PAPER.

30 Aug 2019: Show that the action of the left-invariant vector fields,. Tj (u) = iµji(u). ... ui,. on the matrix A is given by Tj A(u) = A(u) σj , and hence that Ti are generators of the.

19 Jun 2019: dependent toll Tj(yj ), and suppose each user selects a route in an attempt to mini-. ... Tj () so that the equilibrium flow pattern minimizes the average delay in the network.

30 Aug 2019: y1,j = f(tj) g1(tj) ǫ1,j. y2,j = f(tj t) m g2(tj) ǫ2,j.

30 Aug 2019: The variable tj (j = 1,. , 3) records the time interval under observationand takes the values 2, 4 or 6 months. ... logE(Yij|zi; xi; tj ). 1 E(Yij|zi; xi; tj )= α φZi βT xi δtj , (i = 1,. ,

30 Aug 2019: Justify your answers. Suppose now that, in addition to the delay Dj(yj), users of link j incur a traffic-dependent toll Tj(yj), and suppose each user selects a route ... Show that it is possible to choose the functions Tj() sothat the equilibrium flow

19 Jun 2019: where Si1, Si2 correspond respectively to the swimming times of the strong swimmer andthe not so strong swimmer in the ith pair, for 1 6 i 6 3, and Tj corresponds ... a) Show that for j = 4,. 8, Tj has probability density function.

30 Aug 2019: tj,. t6 with tj < tj1. The seventh individual is censoredat time c7 where t3 < c7 < t4.

30 Aug 2019: Define f(tj) and h(tj) to be theprobability mass function and discrete hazard function of failing at tj respectively. ... Thelatter corresponds to the conditional probability of failing at tj, given still alive beyond theprevious failure time point tj1.

30 Aug 2019: Part III, Paper 61. 5. 5. 1) Let = (tj)nkj=1 be a knot sequence such that tj < tjk, and let Sk() be the.

30 Aug 2019: Deduce that for every n 1,. Tn =d1j=1. cn(j)Tj. 2 Define the Weierstrass -function (z) associated to a lattice Λ.

17 Jun 2019: Let Ti = inf{n > 1 : Xn = i}. For each i 6= j letqij = P(Tj < Ti | X0 = i) and mij = E(Tj | X0 = i).

30 Aug 2019: Ifj(θ) is such that tj < θ < tj1, what is the likelihood for θ?