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9 Jan 2009: Wat moet je doen als je helemaal niets be-. grijpt van wat er verteld wordt?Op geavanceerd niveau is het mogelijk dateen volledige reeks van 24 lezingen gewijdwordt aan het bewijs

12 Feb 2009: 3For n = 5, this works out to (5110)/3 = 35, so the intersection form is 9(1)44(1).When n = 6, we have b2 = 6(42 24) 2 = 106 and ... σ = (24 216)/3 = 64, so theintersection form is 21H 8E8.

19 Feb 2009: Determine which of the following polynomials are irreducible in Q[X]:. X4 2X 2, X4 18X2 24, X3 9, X3 X2 X 1, X4 1, X4 4.

31 Jul 2009: σn(f ) f. uniformly as n. 7. Exercise 24. Suppose that Ln : T R is continuous (if you know Lebesguetheory you merely need integrable) and. ... 24. If f : D1 C is analytic and f (D1) D2 show that.

4 Aug 2009: 24. If g is (n 1) times differentiable, and g(0) = g′(0) = = g(n)(0) = 0 then.

12 Aug 2009: MINIMISATION AND REDUCTION OF 2-, 3- AND4-COVERINGS OF ELLIPTIC CURVES. J.E. CREMONA, T.A. FISHER, AND M. STOLL. Abstract. In this paper we consider models for genus one curves of degree nfor n = 2, 3 and 4, which arise in explicit n-descent on

13 Aug 2009: 7 A theorem of Rudin 20. 8 The poor man’s central limit theorem 24. ... 24. Unfortunately, the central limit theorem, in the form given above, ispurely a limit theorem and does not enable us to make statements about.

24 Sep 2009: YRM 的会议。. 不管British Council 给不给我们资金， 我希望五、六个临沂的数学老师会来到剑桥参加Young Researchers in Mathematics (YRM) 的会议。我觉得对你们来说，这个机会很有用。. YRM

8 Oct 2009: 1 21 42 56 24 24α 14 2 0 1 0 0β 15 1 1 0 1 1γ 16 0 0 2 2 2.

8 Oct 2009: Th. and Dynam. Sys. 24 (2004) 1395–1423. [8] A. Harris, K. ... 1, deGruyter, Berlin-New York, 1995. 24. [13] G.P. Paternain, Geodesic flows, Progress in Mathematics, 180 Birkäuser 1999.[14] H.B.