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1 - 10 of 23 search results for katalk:za33 24 |u:www-civ.eng.cam.ac.uk where 0 match all words and 23 match some words.

  1. Results that match 1 of 2 words

  2. Chris Morley

    www-civ.eng.cam.ac.uk/struct/ctm/publications.html
    30 Nov 2007: Magazine of Concrete Research. Special Publication on Recent Developments in Yield Line Theory, 13-24.

  3. Slide 1

    www-civ.eng.cam.ac.uk/cjb/schools/stadium/silcock_files/S3%20Cantilever%20Roof%20design%20Presentation.ppt
    26 Aug 2007: Anti-clockwise moment from coins. = M x 9.8 x (1.5 1) = 24.5M. ... Equating the clockwise and anticlockwise moments gives. M = (101.5 – 17.6) / 24.5 = 3.42 grams.

  4. FRPRCS-8 Full Paper Format

    www-civ.eng.cam.ac.uk/cjb/concplas/10ibell.pdf
    25 Jul 2007: Figure 24 demonstrates its implementation. This system was shown to be practical and even more effective than the equivalent near-surface mounted (NSM) strengthening scheme due to there being no possibility ... Drilled holes Injected paste. Strengthening

  5. Mapping two-way grids onto free-form surfaces P. Winslow S. ...

    www-civ.eng.cam.ac.uk/dsl/publications/Mapping_two-way_grids.pdf
    20 Jul 2007: α25 and β1, β2,. β25.However, only 24 design variables are needed to represent each grid design, due to symmetry anddue to a more advanced parameter smoothing process. ... Loading 1 kPa pressure loadingNumber of regions 25Number of design variables

  6. FRPRCS-8 Full Paper Format

    www-civ.eng.cam.ac.uk/cjb/concplas/19prakhya.pdf
    12 Jul 2007: 06 71.20 0.24 1.09 15.10 2.21 DG2 0.90 0.25 2.10 2.16 9.67 0.68 0.03 0.00 DG3 1.47 ... 29 1.86 0.88 0.94 0.90 DG11 1.24 0.06 1.87 2.29 0.84 1.0 3.53 0.29 DG12 1.24 0.90

  7. New life for plasticity theory

    www-civ.eng.cam.ac.uk/cjb/concplas/01morley.pdf
    11 Jul 2007: In 2007 Pears [24] tested slabs of similar dimensions but with cube strengths of order 65 MPa. ... Fig. 10 Deflection of column stub relative to adjacent slab – 1.0 % fibres [24].

  8. FRPRCS-8 Full Paper Format

    www-civ.eng.cam.ac.uk/cjb/concplas/03baskaran.pdf
    11 Jul 2007: Wood showed the resulting momecould be given as [15]. 6. 22 pxpLxM = 24. , ... then the support moment 12/2pLsm =. and the corresponding span moments are 24.

  9. FRPRCS-8 Full Paper Format

    www-civ.eng.cam.ac.uk/cjb/concplas/14lowe.pdf
    11 Jul 2007: The solution is then rmin= 0.3510.L with the lower bound collapse load from (2) given by pL.L2/m = 24.36.

  10. FRPRCS-8 Full Paper Format

    www-civ.eng.cam.ac.uk/cjb/concplas/02ashraf.pdf
    11 Jul 2007: 24. Table 2 Comparisons between experimental and predicted load capacities. Source Supporting condition No. ... under Bending and Shear’’, IABSE Periodica, Zurich, 36-II, 1976, 105–120. [24] Exner, H., "On the Effectiveness Factor in Plastic

  11. FRPRCS-8 Full Paper Format

    www-civ.eng.cam.ac.uk/cjb/concplas/08denton.pdf
    11 Jul 2007: 12))1(1(24. 23. 2. =hh. hcMwL. p. (19). where h = a / 2L ( = 0.707 a / L) and the width of the yield-lines is equal to a. ... Engineer, Vol. 75, No. 23-24, pp. 403-409. [3] Johansen, K.W., [1962].

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