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25 Feb 2008: l1 =2V 21 sin θ1 cos θ1. g=. 2eV 20 sin θ0 cos θ0g. = ... L =. n=0. enl0 =2V 20 sin θ0 cos θ0. g(1 e).

11 Aug 2008: AdaptingEqs. (4) and (5) for a rotating solution [20] gives. r r r Rr; (6). ... 15. 20. 25. 30. 35. µ. FIG. 3 (color online). Chemical potential as a function ofpumping spot size R.

1 Jul 2008: 4, 8, 14, 17, 19, 20] andsetting c = 0, b = 1 gives the dKP equation. ... Math. Phys. 273 357–78. [20] Pavlov M V 2003 Integrable hydrodynamic chains J.

26 Feb 2008: 1 Two cyclists start 40 km apart and head towards each other, each going at a steadyrate of 20 km per hour.

7 Oct 2008: 4.1features as a dashed line. 8. 0 0.05 0.1 0.15 0.20.82. ... 9. 0 0.02 0.04 0.06 0.08 0.1 0.12 0.14 0.16 0.18 0.20.82.

26 Feb 2008: f (x1)f (x2). =f (αx1)f (αx2). 20. for any α. (If we changed our units of length from metres to centimetres, for instance, we would haveα = 100.).

31 Jul 2008: 13.1.29]. U (a, c, z) = z1cU (a 1 c, 2 c, z), (20). ... 10. 9. 8. 7. 6. 5. 4. 3. 2. K0 10 20 30 40 50.

18 Mar 2008: Eight points have beencomputed for each integral. 0 20 40 60 80 1000. ... w0 20 40 60 80 100. 0. 0.5. 1. 1.5. 2.

7 May 2008: We note that in contrast to the kinetic equations pre-sented in [19] and [20] for the one-component case, Eq. ... 20] C. Connaughton, and Y. Pomeau, C.R. Physique 5 5, 91 (2004).[21] S.

29 Jan 2008: 502, Campus Universitaire, Orsay, F-91405, France. Received 29 June 2007; accepted 15 November 2007; published online 20 December 2007. ... s1. Most experiments took place insidea tube of diameter d = 20 mm; other diameter values.

3 Jul 2008: 4π. jφp(x)d x = d.}. (20). Observe that V2 = V sinceu(φ) = K( jφ σ). ... because h φ W 1,20 (Br)). c θ. p2. 0. (s R)2.

25 Jul 2008: σ/N vs t/N2 (Rouse). Short times finite. 0.1. 1. 0 5 10 15 20.

29 Jan 2008: d = 20 mm corresponding values of Ret sin :48.5, 19.5, 0. ... Control parameter values: At = 3.9 103, d = 20 mm, = 106 m2 / s, and = 1.

1 Aug 2008: 20. 2.4. ω. 100908070. 4.2. 3.8. 50. 3.4. 3.0. 30. 2.6. ... Figure 4.1: Pointwise absolute error for two Filon-type methods. 20. at the endpoints, the second uses both function values and derivatives there.

10 Apr 2008: mπ)4. 20. (mπ)6. ]. (3.5). 128ω5[. 1. (mπ)6. 22. 3. 1. ... 3T 3. 1. 5T 5). 1. (iω)6. (. T 20. 3(T 3.

8 Apr 2008: Mathematical Tripos Part IB 2007. COMPLEX METHODSSummary. 0. Introduction. Aims: to explain the application of complex-variable theory to. (i) Harmonic functions (and hence to Laplace’s equation in two dimensions).(ii) Real integration(iii)

6 May 2008: They also include the bound. k1 max [ /k, γ ] k max [ δ1 , γ (M µk)1 ] (M µk) k, kK, (3.20). ... 9. the last part being obtained from the property (3.11). We replace expression(3.20) by the weaker condition.

25 Sep 2008: while the kinematic equation yieldsu = @x@t ; v = @y@t : (20)Van Dommelen & Shen (1980) made the key observation that (19) de-pends only on x and u, and hence that ... 19) and the rst of (20) can besolved independently of the equations governing y and v.

18 Mar 2008: f0;f1/ suchthat equations (20) are satisfied. For convenience write down equations ŒL0;L1 D 0in full. ... L0;L1; : :; : / is closed for each fixed. We shall establish this fact using equations (20), and d D 0.

13 Jun 2008: It focuses on:.  visual and simple.  the fact that the first 20% of effort gets 80% of the result.

29 Jan 2008: The results were staggering,especially the minimization of a periodic function F (x), x Rn, with 100 vari-ables, although problems with n = 20 were considered large at that time. ... The average values of these counts with m = 2n1 are 931, 1809,3159 and

3 Jul 2008: Now consider the integrated form of the first equation of (1.20) (i.e. ... and corresponding Sobolev norms ‖ ‖Hs on the space of sections defined as in [20].

23 Sep 2008: JOURNAL OF GEOPHYSICAL RESEARCH, VOL. 94, NO. D12, PAGES 14,617-14,628, OCTOBER 20, 1989. ... r {-«Z3m a(sin Zm - Zm cos Zm)} (20). lfOZm AA = • -(z 2 - a 2 sin 2 z)dz - 3 -- •Zm q- «a2(zm- sinzm coszm)} (21).

3 Jul 2008: 11.27). From (11.21) and (11.27) inequality (11.20) follows.Now (11.13), (11.18), (11.19) and (11.20) imply. ... Introduce the majorant. m(t) := sup[0,t]. (1 s)3/2‖η(s)‖Lβ, t t1. 20.

30 Sep 2008: ψ(x, t) = χ(x) exp. (. iEt. ). (20). Substituting for (20) for ψ in the Schrödinger equation yields the time-independent. ... States of the special form (20) are known as stationary states.

3 Jul 2008: 20).Furthermore, as e/0, the rescaled solutions qeððt=eÞ; xÞ converge toqKðxK X0ðtÞÞ in the sense that. ... which implies jj _vjj%cð1CffiffiffiffiffiffiffiEN. pÞ by (2.20). Differentiate with respect to t and.

5 Dec 2008: 20. Cop. yrig. ht. 200. 8 U. nive. rsity. of C.

8 Apr 2008: 19. 2.2 Supersymmetry - Algebra. 20. 2.2.1 History of Supersymmetry. 20. ... century. It has been carefully experimentally verified in many ways, especially during the past 20 years,.

17 Jan 2008: whenever this limit exists. Remarks. • It follows from (1.20) and the definition of a partial deriva-tive (1.14) that. ... To derive (1.52) start from the definition of a directional derivative (1.20), and use the definition of.

24 Apr 2008: 1.4 The ADHM Construction 20. 1.4.1 The Metric on the Higgs Branch 23. ... 20 –. of the D(p 4)-brane [3, 5]. They are the same object!

1 Feb 2008: 0 10 20 30 40 50 600. 5. 10. 15. 20. ... 3è1V6ñEG;=1"J /. i>31Vð@6:v3EF<@> <Cç35è1ENêïé-DF;1þ:C>-A 17>1V6ð"õÂ651V;éDN35;zEF> :@>. 5. 0 10 20 30 400.

1 Jul 2008: ρ0. z. (ρ0f. 20. N2. ψ′. z. )= q′ , (15).

3 Jun 2008: 20. with (x1,x2) = (x,y) yields a second order ODE of the form.

1 Apr 2008: 7b) and, with H0 f 20 L. 2D /g, the undisturbed layer depth,.

27 Jan 2008: 20. for sufficiently small t. We will prove this. Let (U,ϕ) be a chart containing p then, in thesecoordinates, τ will have the form.

3 Oct 2008: 20. Outline proof: first prove Green’s theorem for a rectangle:. y2.