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10 May 2005: developing new techniques of estimating ice type and thickness from remote sensing, based on validation experiments with submarines using SAR, passive microwave and laser profilometry;. ... New EU projects which started in 2001 are:-. further work on the

16 Nov 2005: 21 p. 22), determine the new Hamil-. tonian H(Qi, Pi). Use this to solve for the dynamics under the constraint Q2 = P2 = 0. ... Explain why the. theory of adiabatic invariants cannot be used to calculate the new orbit.

21 Feb 2005: to the grid) pass unnoticed!Bad news:For |θ|, |ψ| = O. (. ... small attenuation already familiar from the analysis of Gauss–Seidel.Good news:Consider just thelarge frequencies.Then.

7 Feb 2005: . . You should find that the(2, 3) element of the new matrix isO(. ... ε3). and that the new matrix has exactly thesame trace asA.

4 Mar 2005: t3). (5.16). Thus,etBetC = et(BC) t 0 only if B andC commute.[Note: It is trivial to prove that commutativityis sufficient, not just necessary.]The good news is, however,

7 Feb 2005: Definition 3.10 (Multistep methods)It is often useful to use past solution values in computing a new value.Thus, assuming thatyn, yn1,. ,

31 Jan 2005: adjacent columns of a matrix, thetotal number of nonzero elements in the new combination of rows or columns is at most five.

19 Jan 2005: It follows from the symmetry ofAand the new assertion(2) that the proof is complete.

25 Jan 2005: The reason for the new step2 is thatf (λ) = 0 implies thatx(k) satisfiesAx(k) = (λ s(k))x(k).

20 Jan 2005: mass does not vanish in general. However, some new topological invariants associated with.