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17 Aug 2023: use contour integration to convert to a linear pencil. 14. Technical point: Spd 𝑇 = 𝜆 Sp 𝑇 :𝜆 isolated,𝑇 𝜆 Fredholm , Spess 𝑇 = Sp 𝑇 Spd 𝑇.

26 Mar 2011: However, in the case at hand wecan say more. There are explicit formulae for the Fredholm determinants ofWiener–Hopf operators with rational symbols. ... Iserles, and S. P. Nørsett, The spectral problem for a class ofhighly oscillatory Fredholm

29 Jan 2019: σess(T) = {z C : T zI is not Fredholm}, ress(T) = sup{|z| : z σess(T)}.

17 Mar 2010: Amer. Math. soc. 130 (2001), 1755–1764. [14] F. J. Dyson, Fredholm determinants and inverse scattering problems. ... Commun.Math. Phys. 47 (1976), 171–183. [15] T. Ehrhardt, Dyson’s constant in the asymptotics of the Fredholm determinantof the sine

25 Jan 2007: Unfortunately, in general,vector RH problems cannot be solved in closed form; their solution can be given in terms of linear integralequations of Fredholm type. ... where C is the unit circle.This equation can be solved in closed form because the

15 Jul 2023: Spd 𝑇 = 𝜆 Sp 𝑇 : 𝜆 isolated, 𝑇 𝜆 Fredholm.

26 Jul 2023: Sp 𝑇 = 𝜆 Ω: 𝑇 𝜆 is not invertible. Spd 𝑇 = 𝜆 Sp 𝑇 : 𝜆 isolated, 𝑇 𝜆 Fredholm.

16 Jul 2018: Algebraic SBTs typically representthe flow around a rigid body through a one-dimensional Fredholm equation of thesecond kind. ... Similarly to other SBT treatments,these relationships are either linear or a one-dimensional Fredholm equation of thesecond

15 Jul 2023: Spd 𝑇 = 𝜆 Sp 𝑇 : 𝜆 isolated, 𝑇 𝜆 Fredholm.

30 Jul 2010: described, then for W(aλ)to be Fredholm it is necessary that |ϕ(ξ)| = O(log |ξ|) as |ξ|. ... 11] H. Brunner, A. Iserles, and S. P. Nørsett, The computation of the spectra of highlyoscillatory Fredholm integral operators.