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14 Jun 2014: s e q ( f =5 , t =1) ## a b b r e v t a g s. ... 1 ## i n c r e m e n t j b y 1. •

19 Jun 2014: m & µ(U) N s (1 log(1/)) log(N), [ 2 ]. (a)(a) (b)(b). (c)(c) (d)(d). Fig. 1. (a) 12.5% uniform random subsampling scheme, (b) CS reconstructionfrom ... b}. The kth relative sparsity is. Sk = Sk(N,M,s) = maxzΘ‖PNk1Nk Uz‖.

6 Feb 2019: b b. q q. Γ3. {τ(Bs)/τ(Bd). Γs. b b. Γ0. . ... 2004: Greub, A.L., Nierste; 2008 A.L. E1. d. b. d. b.

3 Dec 2017: for the first clear one located close to reservoir B—ultimately break up into lines of periodic spots [Fig.1(b)]. ... Reactants are fed through the well-mixed reservoirs A and B (b) Contrast-enhan.

4 May 2010: p′0,0 =. (. 0 1k b. ). p0,0, p0,0(0) = x(0),. ... b. b. lθ(t). y(t). 1. Figure 4: The inverted pendulum. The top position, corresponding to θ = 0, isunstable, but can be rendered stable by adding a fast vertical

19 Oct 2013: Km F6 =I QK 6{ K! x== F6Z? ] =4-<4- 0#B6< =I ]? {? 4g :I KK 0 B"L UBJÔ< =;:I KK ITIT B XABUBJÔ<? ... B"K J5,.#G?=II:; IRÂ0==IIKmG KrKÝG= #g 4< X8 K 4- 'F,.#.=II.

23 Jul 2014: b0 0 1. b1 0. ,. where b = ( ,b1,b0,b1, ) {1}Z is a pseudoergodicsequence. ; ... every finite pattern of 1’s can be foundsomewhere in the infinite sequence b.

26 Jul 2013: a) (b) (c). 0 1.0 0 1.0–1.0. 1.0. FIGURE 2. Trajectories, ξ(t), of surface material points for stroke A (a), stroke B (b), andstroke C ... a). (b). (c). (d ). (e). ( f ). 0 1.0 0 1.00 1.0.

25 Aug 2021: 2. )= R cos. θ. 2. If b > R, clearly there is no scattering. ... dσ. d=. b. sin θ. dbdθ = ( A4E. )21. sin4(θ/2)(1.22).

10 Feb 2023: defined by η. If this condition fails, then there are points a,b as shown on the right in Figure. ... Proof: Let the metric take the form. ds2 = A(r)2dt2 B(r)2dr2 r2dω2d1.