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28 Jun 2024: Between 2005 and 2021 he was with the Department of Informatics of the Athens University of Economics and Business. ... I Papageorgiou, I Kontoyiannis. (2023). (doi: 10.48550/arxiv.2308.00913). Temporally Causal Discovery Tests for Discrete Time Series

17 May 2024: ATHENS UNIVERSITY OF ECONOMICS AND BUSINESS (Greece) 2004 – 2010Associate Professor, Department of Informatics. ... ATHENS UNIVERSITY OF ECONOMICS AND BUSINESS Sept. 2004 – Feb. 2005Visiting Associate Professor, Department of Informatics.

3 Oct 2023: and Loh, P. 2020. Permutation tests for infection graphs. Journal of the AmericanStatistical Association 1–13. ... Influence maximization in stochastic and adversarial settings. London School of Economics statisticsdepartment, UK, 2018.

29 Apr 2014: and on the other, the variances andcovariances of asset returns, which could all be estimated very easily from market data7, therebyproviding a test of the CAPM analysis. ... 1.4 Equilibrium pricing. We cannot pass by this place without pausing to see

5 Jun 2020: Email:tohid.ardeshiri@liu.se‡Department of Informatics, Athens University of Economics and Business, Patission 76, Athens 10434, Greece. ... We apply numerical integration to Berry theoremsand Parseval theorems for a wide range of parameter settings,in

5 Jun 2020: Knight Equity Markets, L.P., Jersey City, NJ 07310, USA. YGao@knight.com†Department of Informatics, Athens University of Economics and Business, Athens 10434, Greece. ... H(Y ) = limi. λH(Yi | Yi1,. , Y2, Y1). Therefore, the renewal entropy estimator

5 Jun 2020: and Elie Bienenstock 3. 1 Knight Equity Markets, L.P., Jersey City, NJ 07310, USA2 Department of Informatics, Athens University of Economics and Business, Athens 10434, Greece3 Division of Applied Mathematics ... H(Y ) = limi. λH(Yi | Yi1,. , Y2, Y1).

24 Jun 2024: A record which remains standing from the first test match.

28 Jun 2024: Reversibility and stochastic networks. FP Kelly. (1979). An algorithm for the most economic link addition in a tree communications network.

28 Jun 2024: Publications. Sense, nonsense and the S&P500. LCG Rogers. – Decisions in Economics and Finance. ... LCG Rogers. – Mathematics and Financial Economics. (2018). 12,. 97. (doi: 10.1007/s11579-017-0198-8).

28 Jun 2024: E Frostig, SM Pitts, K Politis. – Insurance: Mathematics and Economics. ... SM Pitts, K Politis. – Insurance Mathematics and Economics. (2008). 42,.

28 Jun 2024: 2023). (link to publication). What is a Randomization Test? Y Zhang, Q Zhao. –

6 Apr 2024: IOANNIS KONTOYIANNIS. CHURCHILL PROFESSOR OF MATHEMATICS OF INFORMATION. ASSOCIATE MEMBER. FELLOW. Institute of Electrical and Electronic Engineers (IEEE). Institute of Mathematical Statistics (IMS). Asia-Pacific Artificial Intelligence Association

28 Jun 2024: T Fisher, L Drakengren. – Rocky Mountain Journal of Mathematics. Discussion of Adaptive confidence intervals for the test error in classification by Laber and Murphy.

28 Jun 2024: AP DAWID. – Biometrika. (1977). 64,. 291. (doi: 10.1093/biomet/64.2.291). A test for normality against symmetric alternatives.

8 Feb 2010: 6. Write down the model and hypotheses for a test of homogeneity in a two-way contingencytable. ... Show that the likelihood ratio and Pearson’s chi-squared tests are identical to thosefor the independence test.

22 Jan 2022: Show also that. n=1(1)n1andiverges. [This shows that, in the alternating series test, it is essential that the moduliof the terms decrease as n increases.]. ... sequence. Prove that. j=1 ajbj converges. Deduce the alternating series test. Does the series.

4 Mar 2009: Yn N(µY ,σ. 2), where σ is unknown. Derive the likelihood ratio test of size α of H0 : µX = µY againstH1 : µX 6= µY , showing in particular that it can ... are assigned only to one group or the other, we should considera two sample t-test.

18 Jan 2010: bndivergent. 9. (Abel’s test.) Let an and bn be two sequences and let Sn =n. ... Deduce the alternating series test. Does the series. n=1cos(n)n. converge or diverge?

15 Oct 2021: Consider the sequence of distributions. uM =. Mm=M. D|m|δm. Let φ D () be any test function. ... u1φ = (u1? φ̃)(0) = (u2? φ̃)(0) = u2φ. for any test function φ, thus u1 = u2.