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4–1 4 Coherence Selection: Phase Cycling and Gradient Pulses ...
https://www-keeler.ch.cam.ac.uk/lectures/phasen_a4.pdf1 Feb 2001: 4–1. 4 Coherence Selection: Phase Cycling and Gradient Pulses. A multiple-pulse NMR experiment is designed to manipulate the spins in a certain carefully defined way so as to produce a particular spectrum. However, a given pulse sequence usually -
3–1 3 Basic concepts fortwo-dimensional NMR ���� ,QWURGXFWLRQ The ...
https://www-keeler.ch.cam.ac.uk/lectures/2d_a4.pdf1 Feb 2001: 3–1. 3 Basic concepts fortwo-dimensional NMR. ,QWURGXFWLRQ. The basic ideas of two-dimensional NMR will be introduced by reference tothe appearance of a COSY spectrum; later in this lecture the productoperator formalism will be used to predict the -
2d_3_12
https://www-keeler.ch.cam.ac.uk/lectures/2d_letter.pdf1 Feb 2001: 3–1. 3 Basic concepts fortwo-dimensional NMR. ,QWURGXFWLRQ. The basic ideas of two-dimensional NMR will be introduced by reference to theappearance of a COSY spectrum; later in this lecture the product operatorformalism will be used to predict the -
EMBO problems/2
https://www-keeler.ch.cam.ac.uk/lectures/EMBOprobs.pdf1 Feb 2001: 1 24 2 2 2+ ( )In a heteronuclear system a coherence order can be assigned to each spinseparately. -
4–1 4 Coherence Selection: Phase Cycling and Gradient Pulses ...
https://www-keeler.ch.cam.ac.uk/lectures/phasen_letter.pdf1 Feb 2001: 4–1. 4 Coherence Selection: Phase Cycling and Gradient Pulses. A multiple-pulse NMR experiment is designed to manipulate the spins in a certain carefully defined way so as to produce a particular spectrum. However, a given pulse sequence usually -
Basis_Quante–
https://www-keeler.ch.cam.ac.uk/lectures/quant_letter.pdf1 Feb 2001: These details are summarized in thediagram below. 2 J122 J1213 24 12 34. ... 1–24. 1.6.1.2 Ensemble averages; bulk magnetization. In order to compute, say, the x-magnetization from the whole sample, it isnecessary to add up the individual contributions -
Basis_Quante–
https://www-keeler.ch.cam.ac.uk/lectures/quant_a4.pdf1 Feb 2001: These details aresummarized in the diagram below. 2 J122 J1213 24 12 34. ... 1–24. The corresponding equation for cβ is found by left multiplying by 〈β|.
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