Search

Search Funnelback University

Search powered by Funnelback
1 - 9 of 9 search results for katalk:PC53 24 / |u:www.tcm.phy.cam.ac.uk where 0 match all words and 9 match some words.
  1. Results that match 1 of 2 words

  2. General formalism for kinetic energy preconditioning

    www.tcm.phy.cam.ac.uk/~pdh1001/papers/paper14/node4.html
    10 Feb 2004: 24). where we have used the relations.. ... 27). (28). Eq. (24) becomes..
  3. Bibliography

    www.tcm.phy.cam.ac.uk/~pdh1001/papers/paper14/node11.html
    10 Feb 2004: Phys. Rev. 140 (4A), A1133 (1965). 24.
  4. The case of an orthogonal basis

    www.tcm.phy.cam.ac.uk/~pdh1001/papers/paper14/node5.html
    10 Feb 2004: In this case, Eq. (24) becomes..
  5. Formulation of the problem

    www.tcm.phy.cam.ac.uk/~pdh1001/papers/paper14/node2.html
    10 Feb 2004: Next: Principles Up: Preconditioned iterative minimization Previous: Introduction.. Formulation of the problem. A system of noninteracting particles in a potential. is described by.. (1). where. is the single-particle Hamiltonian of the system, with
  6. Experimental Conditions

    www.tcm.phy.cam.ac.uk/~bdj10/propaganda/conditions.html
    12 Nov 2004: 24.) At this point, the Test Proctor will interpret the results of the test.
  7. Tale-09.dvi

    www.tcm.phy.cam.ac.uk/~dek12/tales/Tale-09.pdf
    29 Sep 2004: Therefore, two hermitian opera-tors âx;y = Ax;yp2Hare well dened. As a result the ommutation relations ould be rewritten as[ax;ay = iL (24)[L;ax = iay (25)[L;ay = ... Indeed, we see that the ommutationrelations in the form of Eqs (24,25,26) forms the su
  8. Tale-10.dvi

    www.tcm.phy.cam.ac.uk/~dek12/tales/Tale-10.pdf
    5 Mar 2004: illation, isg() = g(; S1) = vuut 14Æ1T exp 24( Æ1)24Æ1T 35 : (21)5. ... 0: (24)We an redu e its order to get the equationT dfd f = J: (25)6.
  9. Tale-03.dvi

    www.tcm.phy.cam.ac.uk/~dek12/tales/Tale-03.pdf
    1 Aug 2004: Tale 3Supersymmetri Quantum Me hani s1. let us begin from well-known example of a linear os illator,whi h has the Hamiltonian:Ĥ = E ; Ĥ = p̂22m m!2x22 [p̂; x̂ = ih (1)Or, in dimensionless variables:P = vuut 1mh!p; q = sm!h x; (2)H = h! H; H =
  10. ANSWERS2004.dvi

    www.tcm.phy.cam.ac.uk/~cc726/TP1/ExamFiles/exam04sol.pdf
    13 Jan 2004: 0. ux1du. 1 u= 2πi (24). Identifying the sin πx and dividing through, the required result is obtained.

Refine your results

Search history

Recently clicked results

Recently clicked results

Your click history is empty.

Recent searches

Recent searches

Your search history is empty.