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10 Feb 2004: 24 February. Steve Roper. (ITG). Magma fracture in tough materials. 2 March.

10 Jun 2004: a. r – riri. sandsaltricecouscoussugar slope 1.24. Figure 9. The non-dimensional radial excursion, (r ri )/ri , as a function of the aspect ratioa with a < 1.7 for sand, salt, ... A straight line through the origin atslope 1.24 has a regression

9 Mar 2004: J. Fluid Mech. (2003), vol. 497, pp. 167–199. c 2003 Cambridge University PressDOI: 10.1017/S002211200300661X Printed in the United Kingdom. 167. Solidification and compositional convectionof a ternary alloy. By ANDREW F. THOMPSON†, HERBERT E.

9 Mar 2004: 6.3 6.3 24.3 5.89 1.00 3.86 9.6 6.1 3.8 0.7417 6.3 6.3 24.3 10.71 1.00 ... 86 9.6 8.2 5.2 0.8118 6.3 6.3 24.3 20.37 1.00 3.86 9.6 11.3 7.1 0.8919 13.2

9 Mar 2004: are captured by Figure 4.[24] The calculations in Figure 4 illustrate that volcanic.

9 Mar 2004: 6 1.9 1.7ID 20 26.5 1.4 1.3IE 23 20 3.9 10.5IF 12 18 4.0 11.25IG 24 20 4.1 11.5. ... IIA 23 26 5.22 2.62 29 48IIB 17.5 24 5.36 2.68 30 48IIC 15 21 5.94 2.01 25 24IID 28 15 7.02

9 Mar 2004: H.) 3–24 (Springer, Berlin, 1990). 5. Nakada, S., Shimizu, H. & Ohta, K.

9 Mar 2004: Sm =. 0. (ni=1. ψi(0) exp (2Viy))1/2. dy. (2.24). Recall thatn. ... 1 = 2/H0. (3.24)Hence from (3.16), by forming an expansion for ϕi, we find that.

9 Mar 2004: These substitutions transform (2.24) into. uN = I(hN) = Fr(hN) h1/2N. ... Appendix. The functions I and χA.1. The function I(hN). From the definitions (2.19), (2.24) and (2.25) we obtain.

9 Feb 2004: H 0 1!5 2F P12 f P1 1! 4.24! FIG. 2. ... On applicationthe boundary conditions4.23! and 4.24!, we find that. a 5 4.523 102 3, F P15 2 8.42 for Fr5 11.9.