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22 May 2013: Theorem 4.2. The vector of mean hitting times kA = (kAi : i I) is the minimalnon-negative solution to the system of linear equations. {. ... 4.1). Proof. First we show that kA satisfies (4.1). If X0 = i A, then HA = 0, so kAi = 0.If X0 6 A, then HA 1, so

24 Apr 2005: "$#% &'(),-". /'01% 2'3! 4 '5 67-8#% :9;)<=9?>'@'A'.

24 Apr 2005: z D {. KÃ ÈÉ nÇLÌ Ç ÈL « /¡¢ N[@ D  ND/@Dj£w DzH« z@ ¥ @zR@ | g.

3 Feb 2006: Am. J. Physical Anthropology 76; 183–188. Wood JW, Holman DL, O’Connor KA and Ferrell RJ.

10 Nov 2012: Nonparametric regres-sion estimates were analyzed with a sliding windowlength of 1500 ka and a step size of 125 ka. ... Theshorter %NCW record was analyzed with a windowlength of 625 ka and a step size of 62.5 ka.

20 Dec 2012: 2012 Royal Statistical Society 1369–7412/13/75055. J. R. Statist. Soc. B (2013)75, Part 1, pp. 55–80. Variable selection with error control: another look atstability selection. Rajen D. Shah and Richard J. Samworth. University of Cambridge, UK.

17 Mar 2017: Let hA(x) = Px(TA < ) and kA(x) = Ex[TA]. Theorem 2.2. ... kA(x) = 0 x A. QkA(x) =y. qxykA(y) = 1 x / A.

24 Sep 2020: Math. Stat. Learn. 2 (2019), 165–216DOI 10.4171/MSL/14. Mathematical Statistics and Learning European Mathematical Society. On statistical Calderón problems. Kweku Abraham and Richard Nickl. Abstract. For D a bounded domain in Rd;d 2; with smooth

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