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4 Oct 2013: if ψ = 0at r = a then Rnk(a) = Jn(ka) = 0 so for each n, ka = kni with i = 1, 2,.

4 Oct 2013: Its FT is easy to calculate:. f̃(k) =. aaeikx dx =. aa. cos(kx) dx =2 sin(ka). k. (41). so by the Fourier inversion theorem we get. ... 1. π. eikxsin ka. kdk =. {1 |x| < a,0 |x| > a.

3 Feb 2013: Phys Rev Lett 105(16):168101. 17. Guasto JS, Johnson KA, Gollub JP (2010) Oscillatory flows induced by microorganismsswimming in two dimensions.

7 Jan 2013: Phys Rev Lett 105(16):168101. 17. Guasto JS, Johnson KA, Gollub JP (2010) Oscillatory flows induced by microorganismsswimming in two dimensions.

28 Nov 2013: J. Fluid Mech. (2013), vol. 737, pp. 205–231. c Cambridge University Press 2013 205doi:10.1017/jfm.2013.559. Stability of columnar convection in a porousmedium. Duncan R. Hewitt1,†, Jerome A. Neufeld1,2,3 and John R. Lister1. 1Institute of

26 Jul 2013: with similar viscosities (, ) and densities (, ),(b) dimensionless membrane-viscous number, Me U=KA, for two fluids separated by an elastic membrane(thickness t, area modulus KA, density m, bending stiff-ness ... f 2= is an intrinsic viscocapillary

26 Jul 2013: ¤ and compute a matrix F with components fij = cij =( i ¤j ).The minimal-energy stabilizing feedback controller is then given by u = KÀ , whereK = B ¤ F ¡1.

26 Jul 2013: FIG. 4. (Color online) Instantaneous velocity and pressure fields (left) and z component of the vorticity (right) for the in-plane beating oftwo flagella, with ka = kb = 0.05, R = 1, ... Bottom: Variation of the ratio of the minimum to themaximum of the

14 Aug 2013: Let K = Ka/xa, a = 0,. , 3 be a vector field generating a one-parameter group oftransformations of M with orbits Γ.

19 Oct 2013: iσζ̂ kA sinh kh = 0. and from the second (pressure) (). gζ̂ iσA cosh kh = 0. Regarding these as a system of two linear algebraic equations for the two unknown constants ζ̂