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  2. Tutorial Bandit Processes and Index Policies Richard Weber,…

    www.statslab.cam.ac.uk/~rrw1/talks/YETQweber2013.pdf
    14 Nov 2013: 20 / 52. Some constraints. Let xπi = Eπ(Ni)/µi be the mean work-in-system of class i. ... 20 / 52. A mathematical program. Consider the optimization problem. minimizeπ.
  3. A More General Pandora’s Rule Richard Weber, University of ...

    www.statslab.cam.ac.uk/~rrw1/talks/LSEseminar13113.pdf
    14 Nov 2013: Is a generalization of Pandora rule evaporating? 20/57 ,. Yet even more necessity! ... Is a generalization of Pandora rule evaporating? 20/57 ,. Sufficiency. Theorem 1 Suppose u has the form described as necessary, i.e.
  4. Statistics

    www.statslab.cam.ac.uk/~rrw1/stats/index.html
    31 Jul 2013: One in 750,000? One in 20,000? One in 15,000,000? Wikipedai entriies of some famous statisticians: Bayes (Bayesian inference), Gosset (Student's t-distribution), Neyman (Neyman-Pearson test),
  5. Richard Weber's Publications

    www.statslab.cam.ac.uk/~rrw1/publications/papers.html
    8 Nov 2013: C. Courcoubetis and R. R. Weber, Economic issues in shared infrastructures, IEEE/ACM Transactions on Networking, 20: 594-608, 2012.
  6. 22 May 2013: 19. 5.5 Example: optimal parking. 20. i. 6 Optimal Stopping Problems 21. ... 20. 6 Optimal Stopping Problems. More on stopping problems and their solution.
  7. 22 May 2013: 20. 6 Random walks in dimensions one, two and three. 6.1 Simple random walk on Z.
  8. Discussion of Large Covariance Estimation by Thresholding Principal…

    www.statslab.cam.ac.uk/~rjs57/YuSamworthDisc.pdf
    3 Sep 2013: Econo-metrica, 70, 191–221. 2. 800000. 1200000. 1600000. 5 10 15 20. ... 1500. 1600. 1700. (c). 8.0e07. 1.2e08. 1.6e08. 5 10 15 20.
  9. WIAS2013.dvi

    www.statslab.cam.ac.uk/~rjs57/WIAS2013.pdf
    3 Feb 2013: E|f̃n(x0) f(x0)|. c(d){ det(2φ0(x0)). f(x0)2. }1/(d4). February 3, 2013- 20. R. ... 0.00. 0.10. 0.20. 0.30. s. Mar. gina. l Den. sitie. s.
  10. Uniformity of the late points of random walk on Znd for d 3

    www.statslab.cam.ac.uk/~ps422/rwunif2.pdf
    12 Sep 2013: nψ exp(cδ2nβ(d2)ψ. ) ecn. ψ. (2.20). For the second probability on the right side of (2.18), we apply Lemma 2.4 to obtain for allδ (0, ... 1 pd)rd2. (1 O. ( rR. ) O. (1. r2. )). (3.2). 20 JASON MILLER AND PERLA SOUSI. Proof. By Bayes’ formula we
  11. 10 Oct 2013: 20. 2.7 Uniformly integrable martingales. 21. 2.8 Backwards martingales. 23. 2.9 Applications of martingales. ... Xn‖p p. p 1‖Xn‖p,. 20. where recall that Xn = supkn |Xk|.

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