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20 Dec 2013: But this is basis-dependent: a. Part 3 General Relativity 4/11/13 20 H.S. ... T : Tp (M). Tp (M) Tp(M). Tp(M) R. (2.20). where there are r factors of Tp (M) and s factors of Tp(M).

17 Dec 2013: Purcell’s three-link swimmer [17] was optimized[18–20], and so was a simpler version of the swimmer usingthree aligned spheres [21, 22]. ... 20)As f and α are both time-periodic function, we can use anintegration by part to obtain.

28 Nov 2013: 0.1. 0.5. 0. (c). 0.40.30.20.1 0.5 0.40.30.20.1 0.50. FIGURE 2. Contours of the growth rate Re{σ̂} (as marked) ... 0.25. 0.20. 0.15. 0.10. 0.05. 0 0.5 1.0 1.5 2.0. (a) (b) 15.

17 Nov 2013: On a good day, I could probably get through about 20% of them.

4 Nov 2013: Corrigendum 443. 0. –20. –40. –40. –80. –120. –60. –80. –100.

4 Nov 2013: The measurements of k can be fitted by an ap-proximate scaling k Ra0:4, though the data also hint at apossible decrease in the exponent for Ra > 20 000 ... 20] Counts from a plume-tracking algorithm suggest a scalingexponent of 0:96 0:05 for the rib

4 Nov 2013: 20. 40. 60. 80. 100. 120. 1 2 3 4 5 6 7. ... E. Huppert, J. A. Neufeld and C. Strandkvist. 0 20 40 60 80 100.

4 Nov 2013: The flow enters a new regime in which thebending stresses in (1) can be neglected almost every-where, resulting in a standard viscous gravity-currentbalance [7,20]. ... 19] L. Hocking, Q. J. Mech. Appl. Math. 36, 55 (1983).[20] H.

4 Nov 2013: Comparingtheir figure 3 and (2.20) with our figure 2 and (2.11) highlights the importance ofthe specific system to the current behaviour. ... 10 cm above the porous medium within a large cylinder ofradius rC = 5.75 cm as it drained through the straws of

4 Nov 2013: In the inset offigure 2 (main text), this scatter is reduced by taking a 20-point running average.