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5 Mar 2002: Such spectra have proved to beenormously useful in structure determination, and are responsible for the ex-plosive growth of NMR over the past 20 years or so.

5 Mar 2002: 2. = 20 log10(. ωnew1 /2π. ωinit1 /2π. ). This expression can be used to find the correct setting for the attenuator.As the duration of a pulse of a given flip angle ... power ratio in dB = 20 log10(. τinit. τnew. ). For example, suppose we have

5 Mar 2002: d 30 transferred to 20, 30 and 60. e 30 and 60 transferred to 30 and 60.

5 Mar 2002: a) (b). (c). -20 -1010 20. -1. -0.5. 0.5. 1. -20 -10 0 10 20. ... 0.5. 1. -20 -10 10 20. -1. -0.5. 0.5. 1. MxMy.

5 Mar 2002: 4.13. tacqtacq /20. 0 π/4π/8 π/2phase. Fig. 4.13 The top row shows sine bell and the bottom row shows sine bell squared weighting functions fordifferent choices ... Suppose that the transmitter is placed in the middle of the shift range andthat a 90

5 Mar 2002: 2.6 Strong coupling 2–15. 3424 1213. 12 34. 0 20 10040 60 80. ... frequency (Hz) –ν0,1. ν0,2 = –90. ν0,2 = –50. ν0,2 = –20.

5 Mar 2002: the mixing period and continued to evolve at 20 Hz during t2.The processes by which these signals are transferred will be discussed in thefollowing sections. ... Finally, consider the spectrum shown in c. Here there are two peaks, one atF1 = 20 Hz, F2 =

12 Mar 2002: 8–20. For this spectral density function, the maximum contribution at frequency ωis found when τc is 1/ω; this has important consequences which are described inthe next section.

12 Mar 2002: 9–20. sampled at regular intervals. After transformation the resulting spectrumdisplays correctly peaks with offsets in the range –(SW/2) to (SW/2) where SWis the spectral width which is given

23 Jul 2002: 4–20. them to the edge of the spectrum so that they are less likely to obscurewanted peaks.