Search

29 Jan 2010: It isthen clear that for some non-zero invariant v Vq the mapping Φq,1 is given by. ... may be represented by some k GẐ, and then. σ : ZQDf Nf k 7 ZQDẐNf k.

29 Nov 2010: Find this solution to some reasonable accuracy using a pocket calculator or thecalculator on your computer (remember to work in radians!), and justify the claimed accuracy ofyour approximation. ... norm. Show, however, that T is a contraction under the

29 Jan 2010: The second is to. construct some extensions of motives related to elements of higher Chow groups and to. ... as in 1 is probably known to some experts (see for example the penultimate paragraph of.

22 Nov 2010: It follows that A and B lie on some regular polygon Π (withcentre O). ... In the case of agroup G which acts as the symmetry group of some transitive set of order |G|,Conjecture C may be deduced easily from Conjecture B.

29 Jul 2010: For this weneed lower bounds on some of the ||vi||. The hypotheses in parts (a), (b)and (c) of Theorem 1.2 are used to give successively better lower bounds,and ... F(x)| max(|a|, |b|, |c|) ||x||3 < 1. Since F(x) = f(u,v,w) for some u,v,w Z it follows

29 Jan 2010: Proof. We can assume that c = [Z′/k] for some integral closed subscheme Z′/k. ... 2.1.1. We recall some basic facts about modular curves (see [4] or [9]).

17 Feb 2010: ii) For some K, some ω V Kπ , and some u, v O(MK) Z Q,MK (C). ... For some positive integer N, the correspondence NXp(Tp) annihilatesPic0(MK), and since p 1 > 2.

12 Oct 2010: for some λ,α,β,γ,δ Z[n11,n12,. ,n33,a,b,c,. ,m]. Moreover if N is diagonal. ... for some a,b OK then substitute x xay bz and go to Step (ii).(iv) Return α.

25 Nov 2010: 1 σan τcn and g τn g1 σbn τdn for some a,b,c,d Z/nZ. ... for some A GLm. Putting g = [A,B] wehave φ′′ = gφ.

17 Dec 2010: But by (b), this means that some finite intersectioc oi’ elements of CD is empty, a contradiction. ... But then the W,, defined has the further property that if W, $ W,, for some B’, then W,.$ W,,,.