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1 Feb 2010: Find a conjugate harmonic functionv(x, y), that is, a function v such that u and v together satisfy the Cauchy-Riemann equations. ... Show that there is an analyticfunction H : C C such that h(z) = exp H(z) for all z.

27 Jan 2010: Use a suitableLagrange resolvent to find a Q(µ3) such that K = Q(ζ3, 3. ... Use (ii) to show that there exists b K such thatdet(σiσjQ1(b)) ̸= 0.

29 Jan 2010: The irreducibility of Sp(χ) for such a prime pin conjunction with a) implies that Φq,χ = 0. ... Since GẐ acts transitively on |MK |,. there exists a positive constant cn Q such that for every x |M|,.

12 Oct 2010: Suppose then that g is a. quartic with J = 0 such that z(g) = z(g). ... We now fix such a u and put αi = B(ei, u)where e1, e2, e3 K3 are the standard basis vectors.

22 Nov 2010: Let t = a! and d = t. By Ramsey’s theorem, there exists a positive integer b such that whenever[b](t) is ka-coloured, there exists a monochromatic subset of order ... d. Letu = b a 1 and v = u tr. By Ramsey’s theorem again, there exists a positive

23 Dec 2010: x A)(y B)φ(x,y)HSS. Let α > rank B such that Vα HSS HSS, then Vα HSS is the required set. ... junction and negation. Now suppose φ df (y)ψ(x,y). If φ( R) holds in B, there exists S B such that ψ( R,S) holds in B.

18 Nov 2010: 14. Is there an uncountable family S PN such that A B is finite for all distinct A, B S? ... such that. (qn qn1)2 converges? A.G.Thomason@dpmms.cam.ac.uk - 1 - 18 November 2010.

29 Jan 2010: Therefore there are constants a, b, c k such that if v, v′ Spand w IndGB δ1/2, then. ... π′′ = I(1)0, then we can choose w such that HomGw (πw.

3 Nov 2010: Recall that the existence of such a mini-mizer was proved in lecture.). ... b) Choose numbers a1, b1 such that 0 < a1 < a < b < b1 < 1, and set, for x R and n = 1, 2, 3,. ,.

17 Dec 2010: such that. MIA A M/B. ll 1r MA oh_ MB. commuts up to natural isomorphism. ... For g : Y-, B in M/B we expect IIh 0 Y E M/A to be such that a fibre (II,, 0 Y)n is the modest set of sections