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12 Mar 2013: Show that I T hasa square root, i.e., there exists S B(X) such that S2 = I T. ... invertible operator T : X X such that Txn = yn for all n N.

8 Jan 2008: v) If ‖a b‖1 = ‖a‖1 ‖b‖1, does it follow that we can find α, β F,not both zero, such that βaj = αbj for all 1 j n? ... Give reasons. (vi) If ‖ab‖ = ‖a‖ ‖b‖, does it follow that we can find α, β F,not both zero, such that

4 Feb 2008: Let P be the set of all p Q such that 2 < p2 < 3. ... c) If A and B are closed subsets of R such that 1 A, 1 B and [1, 1] A B, thenA B 6=.

8 Mar 2024: αd OK such that. OK = α1Z. αdZ.Such a collection of elements α1,. , ... 14 PÉTER P. VARJÚ. of this form. So no such π1 may exist.

5 Jun 2020: According to Occam’s razor, the simplest such explanation isthe one that should be favored. ... Given a string x, suppose wefocus on a special sub-class of programs p that produce x, namely, programs thatfirst describe a set B of strings such that x B,

31 Jan 2024: G = H1 BH2 BH3 BH4 B BHn = {e}. such that each quotient Hi1/Hi is simple. ... Since they have the same cycle type, there is a σ Sn such that (a b c) = σ(1 2 3)σ1.

25 Nov 2023: Let θ : A B be a -homomorphism from a Banach -algebra A to a C-algebraB. ... H) such thatz(T) = T, where z(λ) = λ for all λ K.

22 Feb 2022: Show that for any b C, there exists a sequence of points zn D(a,R)with zn 6= a such that zn a and f(zn) b as n. ... Find such a sequence when f(z) = e1/z, a = 0 and b = 2.[A much harder theorem of Picard says that in any neighbourhood of an essential

22 Oct 2020: Let B(G,F) be the (extended) Bruhat–Tits building of G(F). For any x B(G,F), there is asmooth affine group scheme Gx over OF such that ... a choice of basis b for Λ such that the embeddings of buildings (3.3.1) and (3.3.2) induceembeddings of the

21 May 2005: for some x,y Z with (x,y) = 1, then there exist a,b Z such that p = a2 b2. ... αn be algebraicintegers in K such that the discriminant D(α1,. ,αn) is a square-free non-zerointeger.

5 Jun 2020: N = M2 pY11 pY22 pYπ(n)π(n) , (6). where M 1 is the largest integer such that M2 divides N, and theYi are now binary. ... Actually Chebyshev came pretty close to proving the PNT. Forexample, using Theorem 1 in a slightly refined form, he was ableto

5 Jun 2020: Theorem Almost sure invariance principle Let X be a nitevalued stationary process such. ... fB t t g such that for any. R t B t O t as.

15 Oct 2020: The least such n iscalled the order of g.). (b) Show that there exists a positive integer n such that gn = e for all g G. ... Can such a group beinnite? 8. Let G be a group of even order.

15 Oct 2021: b) Let f L2(U). For each γ > µ, denote by uγ the unique solution of (†). i) Show that for any γ > µ there exists wγ H10 (U) such that:. ... b) Show that there exists a constant C > 0, depending only on n, such that:.

22 Nov 2012: Show that, for such a map,. dimH f (M ) 61α. ... Prove that the limit set for such a group is totallydisconnected.

9 Nov 2020: Now suppose b G(L) is such that νb X(T) is dominant, hence defined over Zp. ... Itsuffices to prove that also descends to R(a,b). The coordinates ti induce a Frobenius-equivariant map RG R(a,b), such that the compositeR(a,b) RG

14 Oct 2009: On the other hand, show that if fn does not converge uniformly to f , then we can find aconvergent sequence xm x in [a, b] such that fn(xn) does not ... Give an example of a sequence of uniformly continuousfunctions fn on R, such that fn converges

1 Feb 2022: b) Find a condition on s such that x 2 Hs(Rn). ... 2u u = f. b) Show further that there exists C > 0 such that kukHs4.

1 Feb 2010: Find a conjugate harmonic functionv(x, y), that is, a function v such that u and v together satisfy the Cauchy-Riemann equations. ... Show that there is an analyticfunction H : C C such that h(z) = exp H(z) for all z.

22 Oct 2001: 3. =. (π. p4. )3. 6= 1. Proof. Let B {1, 4, 7} such that{p1p2B 6 1 (mod 9)p3p4B 6 1 (mod 9). ... Take a prime π Z[ω] such that N(π) B (mod 9).