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19 Oct 2023: 0.0380] [0.0177] [0.0083] [0.0052]. Log(maint cos ts /m2) - - - -0.0529- - - [0.0139]. ... Ene rgy clas s FG 0.0003[0.0528]. Log(maint cos ts /m2) 0.1493 [0.0545].

23 Oct 2023: q1 = Q1 cos λ P2 sin λ, q2 = Q2 cos λ P1 sin λ,. ... p1 = Q2 sin λ P1 cos λ, p2 = Q1 sin λ P2 cos λ.

20 Jan 2023: φ(s,v) = α(s) r(n(s) cos v b(s) sin v). where n = n(s) and b = b(s) are the normal and binormal vectors of α. ... φ(u,v) = ((2 v sin(u/2)) sin u, (2 v sin(u/2)) cos u,v cos(u/2)).

17 Jan 2023: V=abc(1-cos2β)1/2=2449.39b=1/b=0.096637a=bcsin(α)/V=bc/V=0.066949c=absin(γ)/V=ab/V=0.064081α=γ=90 cos(β)=-cos( ... β)=0.174249 β=79.965. aa=1=|a||a|cos(ang)=0.06694915.168cos(ang) ang=10.02.

3 Oct 2023: a b = ab cos θ. (23). a. bθ. Figure 10: Angle used in the definition of the scalar product a b. ... 26). 4. If a b = 0, and a, b 0 then cos θ = 0, necessarily, i.e.

26 Jan 2023: The general solution is. x(t) = X R sin(!Bt ) and y(t) = Y R cos(!Bt ) (1.2). ... m!B. Y = y(t) R cos(!Bt ) = y ẋ! B= y.

1 Dec 2023: the boundary condition to be imposed is. u=cos θ and τrθ =%Bi sgn(y) at r =1 (2.7a,b). ... balance. But FEAE′ =2FAE, where FAE =rEI Bi[2(πβ2) cos β2 sin β2] is the force on the section AE (see appendix B.1).

1 Dec 2023: for transverse waves and. ψ =0, ψy =aπ cos πx0, on x=x0 a sin πx0 and y=0, (2.17a,b). ... 12 π. 2y= 14 π sin(2πy) cos(2πx)12 π. 2y, (3.11). Dow.

16 Oct 2023: λk(A) =λk(C). λk(B)=. 12µsin2 12πkh1 2µsin2 12πkh. |λk(A)| 1, k = 1.M. ... iγ where γ = 2 cos(πh) for = 1,.

4 Feb 2023: a) U = {(u,v) R2 |u > v}, σ(u,v) = (u v, 2uv,u2 v2);(b) U = {(r,z) R2 |r > 0}, σ(r,z) = (r cos(z),r ... σ(u,v) = (sech u cos v, sech u sin v, tanh u).

5 Mar 2023: Prove that itscircumference is 2π sin(ρ) and that it bounds a disc on S2 of area 2π(1 cos(ρ)). ... sin(A) sinh(c) = sinh(a). (b) Deduce that for a general hyperbolic triangle, one has.

1 Dec 2023: u= eσ cos(2πy). I0(σ)1, v=0. (3.2a,b). Given this fixed, known velocity the concentration simply evolves via the advection–diffusion equation (2.7). ... u(x, y, t)= eσ cos(2πy)Rc′(x,y,t) 1. 0eσ cos(2πs)Rc. ′(x,s,t) ds1. (4.4).

17 Oct 2023: A B) = B ( A) A ( B). (A B) = (B )A (A )B A( B) B( A). ( ... Bound orbit in point mass potential:. r =a(1 e2. )1 e cos ϕ.

29 Sep 2023: b) Starting from M = E e sin E, r = a(1 e cos E) and h = na2. ... cos g =(1 ra) e. 2. e(1 ra) e, (6). and so that cos g = cos M O(e2).

1 Dec 2023: pxpy. )=S(Q;B, 1). (cos θsin θ. )and. (ψxψy. )=Q. (sin θcos θ. ), ... x, y)= 13 B2a2(cos 3θ 3 cos θ, sin 3θ 3 sin θ).

26 Mar 2023: β s. [h3(. hs. cos α sin α)]. (3.11). We note that (3.11) reduces to (2.1a,b) only under the assumption |h/s| | tan α|. ... sk1N = skN vk1N t, vk1N =(. hk1n1)3. cos α. 3(skN sn1), (A3a,b).

1 Dec 2023: tan δ = (Ws 1) sin Φ(Ws 1) cos Φ Q, (2.18). ... Fx(δ, n, Bi) Bifx(|δ|) sgn(δ) Fz(δ, n, Bi) Bifz(|δ|) sgn(cos δ), (3.6a,b)for some functions fx and fz.

31 Aug 2023: cos(. kx φ1 φ22. )︸ ︷︷ ︸. g(x). = f (t) g(x). ... 0. q(t) = Aeω02Q t cos(ωt ϕ) q(t) = (At B)eω0t q(t) = Ae.

2 Aug 2023: 10. sin 2𝜔𝑓 2 cos 𝜔𝑓 = sin 2𝜔0 2 cos 𝜔0 , (2.5). ... volume 𝑉 = 𝑉0, where. 𝑉 = 22(sin 𝜔1 sin 𝜔3) cos 𝜔1 = 𝑉0.

6 Feb 2023: a) U = {(u,v) R2 |u > v}, σ(u,v) = (u v, 2uv,u2 v2);(b) U = {(r,z) R2 |r > 0}, σ(r,z) = (r cos(z),r ... σ(u,v) = (sech u cos v, sech u sin v, tanh u).