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12 Nov 2023: b) 2(cos θ θ sin θ)/ cos2 θ. (c) t(1 2 ln t). ... a tan1 y. a). H14. (b) J = 1b(1 eax cos bx) a.

1 Nov 2023: 5. Diagonalise the quadratic form in R2 defined by. F(x, y) = (a cos2 θ b sin2 θ) x2 2(a b)(sin θ cos θ) xy (a sin2 θ b

23 Oct 2023:   cos φ sin φ 0sin φ cos φ 00 0 1. ... ψ̇ φ̇ cos θ. . (b) [optional extra] Calculate the matrix B = R>Ṙ and verify that it is antisymmetric.

3 Oct 2023: 13. Calculate the following sums:. (a)5. n=1 sin(nθ). (b)N. n=1 cos(nθ). ... a) (x,y) = (a cos θ,b sin θ),. (b) (x,y) = (a cosh θ,b sinh θ),.

6 Oct 2023: I0(x) =1. π. π. 0. ex cos θ dθ. Oscillatory Integrals and Stationary Phase. ... a). 1. 0. cos(. x tp). dt , with p > 1 , real ,. (b). π. 2. 0. (. 1 (. 2θ. π. ))γ. cos(.

24 Nov 2023: 26). 4. If a b = 0, and a, b 0 then cos θ = 0, necessarily, i.e. ... We have. a b = ab cos θ,(2, 1, 0) (3, 0, 1) =. 5. 10 cos θ,. cos θ = 6/. 50,. and thus θ = cos1(6/.

1 Dec 2023: X = 0 is given byF′ G = c0, (cos X σ0) G sin XF = 0, (4.4a,b). ... Θ = Ae(1κ2)τ cos κX Z, W = Ae(1κ2)τ cos κX, (5.1a,b)for any amplitude A.

1 Dec 2023: sin α) 2π(2 cos φ, sin φ)/ log Bi1 (see (3.2)). ... Ṽs =U cos(φΦ), ω̃=URH. sin(φΦ). (4.5a,b). Dow. nloa. ded. from. htt.

24 Jul 2023: Ω sed = mg16πa2η. ln(a. b. )(κ̃x sin θ κ̃y cos θ. ... sin θ, (3.40). Usedx = mg. 8πaηln(a. b. )cos θ sin θ, (3.41).

10 Oct 2023: a) σiσj = Iδij iǫijkσk,. (b) σ2σσ2 = σ,. (c) exp(iθn σ/2) = I cos(θ/2) in σ sin(θ/2). ... t(A B) t2. 2[A, B]. t3. 12{[A, [A, B]] [B, [B, A]]}. ).

23 Oct 2023: q1 = Q1 cos λ P2 sin λ, q2 = Q2 cos λ P1 sin λ,. ... p1 = Q2 sin λ P1 cos λ, p2 = Q1 sin λ P2 cos λ.

19 Oct 2023: 0.0380] [0.0177] [0.0083] [0.0052]. Log(maint cos ts /m2) - - - -0.0529- - - [0.0139]. ... Ene rgy clas s FG 0.0003[0.0528]. Log(maint cos ts /m2) 0.1493 [0.0545].

20 Jan 2023: φ(s,v) = α(s) r(n(s) cos v b(s) sin v). where n = n(s) and b = b(s) are the normal and binormal vectors of α. ... φ(u,v) = ((2 v sin(u/2)) sin u, (2 v sin(u/2)) cos u,v cos(u/2)).

17 Jan 2023: V=abc(1-cos2β)1/2=2449.39b=1/b=0.096637a=bcsin(α)/V=bc/V=0.066949c=absin(γ)/V=ab/V=0.064081α=γ=90 cos(β)=-cos( ... β)=0.174249 β=79.965. aa=1=|a||a|cos(ang)=0.06694915.168cos(ang) ang=10.02.

3 Oct 2023: a b = ab cos θ. (23). a. bθ. Figure 10: Angle used in the definition of the scalar product a b. ... 26). 4. If a b = 0, and a, b 0 then cos θ = 0, necessarily, i.e.

26 Jan 2023: The general solution is. x(t) = X R sin(!Bt ) and y(t) = Y R cos(!Bt ) (1.2). ... m!B. Y = y(t) R cos(!Bt ) = y ẋ! B= y.

1 Dec 2023: the boundary condition to be imposed is. u=cos θ and τrθ =%Bi sgn(y) at r =1 (2.7a,b). ... balance. But FEAE′ =2FAE, where FAE =rEI Bi[2(πβ2) cos β2 sin β2] is the force on the section AE (see appendix B.1).

1 Dec 2023: for transverse waves and. ψ =0, ψy =aπ cos πx0, on x=x0 a sin πx0 and y=0, (2.17a,b). ... 12 π. 2y= 14 π sin(2πy) cos(2πx)12 π. 2y, (3.11). Dow.

16 Oct 2023: λk(A) =λk(C). λk(B)=. 12µsin2 12πkh1 2µsin2 12πkh. |λk(A)| 1, k = 1.M. ... iγ where γ = 2 cos(πh) for = 1,.

4 Feb 2023: a) U = {(u,v) R2 |u > v}, σ(u,v) = (u v, 2uv,u2 v2);(b) U = {(r,z) R2 |r > 0}, σ(r,z) = (r cos(z),r ... σ(u,v) = (sech u cos v, sech u sin v, tanh u).