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10 Oct 2023: a) σiσj = Iδij iǫijkσk,. (b) σ2σσ2 = σ,. (c) exp(iθn σ/2) = I cos(θ/2) in σ sin(θ/2). ... t(A B) t2. 2[A, B]. t3. 12{[A, [A, B]] [B, [B, A]]}. ).

23 Oct 2023: q1 = Q1 cos λ P2 sin λ, q2 = Q2 cos λ P1 sin λ,. ... p1 = Q2 sin λ P1 cos λ, p2 = Q1 sin λ P2 cos λ.

20 Jan 2023: φ(s,v) = α(s) r(n(s) cos v b(s) sin v). where n = n(s) and b = b(s) are the normal and binormal vectors of α. ... φ(u,v) = ((2 v sin(u/2)) sin u, (2 v sin(u/2)) cos u,v cos(u/2)).

17 Jan 2023: V=abc(1-cos2β)1/2=2449.39b=1/b=0.096637a=bcsin(α)/V=bc/V=0.066949c=absin(γ)/V=ab/V=0.064081α=γ=90 cos(β)=-cos( ... β)=0.174249 β=79.965. aa=1=|a||a|cos(ang)=0.06694915.168cos(ang) ang=10.02.

3 Oct 2023: a b = ab cos θ. (23). a. bθ. Figure 10: Angle used in the definition of the scalar product a b. ... 26). 4. If a b = 0, and a, b 0 then cos θ = 0, necessarily, i.e.

26 Jan 2023: The general solution is. x(t) = X R sin(!Bt ) and y(t) = Y R cos(!Bt ) (1.2). ... m!B. Y = y(t) R cos(!Bt ) = y ẋ! B= y.

1 Dec 2023: the boundary condition to be imposed is. u=cos θ and τrθ =%Bi sgn(y) at r =1 (2.7a,b). ... balance. But FEAE′ =2FAE, where FAE =rEI Bi[2(πβ2) cos β2 sin β2] is the force on the section AE (see appendix B.1).

1 Dec 2023: for transverse waves and. ψ =0, ψy =aπ cos πx0, on x=x0 a sin πx0 and y=0, (2.17a,b). ... 12 π. 2y= 14 π sin(2πy) cos(2πx)12 π. 2y, (3.11). Dow.

16 Oct 2023: λk(A) =λk(C). λk(B)=. 12µsin2 12πkh1 2µsin2 12πkh. |λk(A)| 1, k = 1.M. ... iγ where γ = 2 cos(πh) for = 1,.

1 Dec 2023: u= eσ cos(2πy). I0(σ)1, v=0. (3.2a,b). Given this fixed, known velocity the concentration simply evolves via the advection–diffusion equation (2.7). ... u(x, y, t)= eσ cos(2πy)Rc′(x,y,t) 1. 0eσ cos(2πs)Rc. ′(x,s,t) ds1. (4.4).