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17 Jun 2019: b)dy. dxsin x y cos x = 12 sin 2x [5]. ... 2yx=y. (2x2 y)dxdy. Evaluate the integral. [10]. (b) The equation r = (1 cos θ) defines a closed surface in three dimensions.

17 Jun 2019: σ(u,v) = ((a b cos u) cos v, (a b cos u) sin v,b sin u),. ... ψ(x) =15a. cos(πx. 2a. ). 25a. sin(πxa. ),. in the region a x a, and zero otherwise.

19 Jul 2019: cos. (B C. 2. ) sin. (A. 2. )= 2 sin. ... G1. (i) AC = 1, B = C =π. 3radians; (ii) cos C = cos A =. 3. 4, cos B = 1. 8. 12. G2. (i) 6 π; (ii)3π.

17 Jun 2019: φ(r,θ) = A B log r. n=1. [rn(An cos nθ Bn sin nθ) rn(Cn cos nθ Dn sin nθ)]. ... where An, Bn, Cn and Dn are constants. [10]. Obtain the solution for φ(r,θ) given the boundary conditions φ(a,θ) = U andφ(b,θ) = V cos θ.

17 Jun 2019: u(x,y,0) =. m=1. n=1. Amne β. 2x sin(mπx) cos. (. 2n12 πy. ). ,. ... exp(M) =. . . . . cosha sinha 0 0sinha cosh a 0 00 0 cos b sinb0 0 sinb cos b.

17 Jun 2019: Φ(r, θ) =. n=0. (Anr. n Bnrn1)Pn(cos θ). for constants An, Bn. ... The temperatureon the boundaries of the shell is. T (a, θ) = T0 T1 cos θ, T (b, θ) = T2 T3 cos θ ,. for constants T0, T1, T2, T3. Determine the

17 Jun 2019: By settingthe former equal to cos θ|a|b̂, where b̂ is a unit vector along b, show that. ... cos θ =a b|a||b|. Explain why this is a sensible definition of the angle θ between a and b.

30 Aug 2019: 1 < p <. Letf (x) = a cos nx b sin nx,. ... n. b) Let. f (x) =. k=0. ak cos 5kx, ak > 0,.

30 Aug 2019: b) By considering f (x) = cos kx show that we cannot have a small-o estimate. ... q(x)| 6 n1 x2. at the n zeros of Tn ,. then|q(x)| 6 |T ′. n(x)| , |x| > cos π. 2n.

17 Jun 2019: A = cos(. θ. 2. )I sin. (θ. 2. )E1E2,. where θ is a scalar. ... 6]. (b) A curve is given parametrically by. x = cos θ, y = cos(4θ), 0 < θ < π.