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23 Oct 2014: ui(0) = sin( πxi. b. ), u′i(0) =. π. b. gd(xi) cos. ( ... b. gd(xN ) cos. ( πxNb. ))T,. (39). where U (t) denotes the N -dimensional vector with entries ui(t) u(xi, t),.

20 Oct 2014: 4. Let (fn) be a sequence of real-valued continuous functions on a closed, bounded interval [a,b], and. ... m=1 mam cos mx. (b) Show that f(x) =. m=1 am sin mx defines a continuous function on [π,π], but that the seriesm=1 mam cos mx need

22 Dec 2014: eπ2. sinh(π) j = 0,. j cos( jt)sin( jt)π2. j21. j Z+. ... a = 0, b = π, (t [0,π],q(t) = 20 cos(2t)), α1 6= 0, β1 6= 0, α2 = β2 = 0,.

9 Nov 2014: 2. V (t) =µπ2c2. 4L. n=1. n2[An cos. (nπct. L. ) Bn sin. ... m=1. i=1. [Cmi cos mθ Dmi sin mθ] cos(kmict) Jm(kmir). (5.32).

14 Oct 2014: obtain:. Φ(ϕ) = A sin(λϕ) B cos(λϕ),. with positve constants A, B. ... Aλrλ Bλr. λ) sin(λϕ) (Cλrλ Dλr. λ) cos(λϕ). E0 F0 ln(r).

3 Feb 2014: From simple trigonometry, this leads tothe following expressions. jGxx j sin2 a; jGyy j cos2 a; jGxy j sin a cos a (1). ... a diameterwith end-points ðjSxx;jSxyÞ ðj sin2 a;j sin a cos aÞ and ðjSyy; jSxyÞ ð0; j sin a cos aÞ; see Fig.

13 Oct 2014: b) Now consider an almost ideal FJC with N monomers of type a. ... Show that these can be written as. W(n)(x) = A cos(k(n)x) B sin(k(n)x) D cosh(k(n)x) E sinh(k(n)x) ,. and

25 Mar 2014: xz. -y. -xz zz. (a) (b). angle = πJt. 2Î1yÎ2z2πJ12tÎ1zÎ2z cos (πJ12t) 2Î1yÎ2z sin (πJ12t) Î1x. ... cos (τ) sin (τ)Îy sin (τ) sin (τ)Îx Îx Spin echoes 20.

6 Feb 2014: S = b cos θ tan γffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi1 cos2θ tan2γ. p ; [2]. ... cos γA1cos γB1. =cos γA2cos γB2. [21]. must be satisfied to enable stacking.

29 Aug 2014: û% |r =1 = K cos(nθ ). . 0. cos φ cos θ sin φ. ... Thus, the previous equations canbe put in the form. s û% = K cos φk.