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cos (. ). sin (. (. cos. )). cos (. ). sin (. (. )). sin (. ). cos (. (. sin. )). sin (. ). cos (. (. cos. )). cos (. ). sin (. (. cos. )). sin (. ). cos (. (. cos. [. sin. 1. 0. ]. sin. )). cos (. ). cos (. (. cos. )). cos (. ). sin (. (. cos. )).

τ. r. r2 r2. cos φ sinτ. τ. 2 r2. rsin φ cos. ... J12 =2 r2 cos φ sin. τ. r. r2 r2. cos φ cosτ.

T. B. it. I. I. I. I. I. =. -. =. 1. 3. cos. sin. ,. with. I. : I. ème. own pseudo-pulsation of the deadened system. ... Controls. DYNA_LINE_TRAN NEWMARK. C.L. DIRICHLET BY LOAD. 6. Results of modeling B.

cos. ,. ,. cos. B. éq 4.3.4-4. Code_Aster. Version. ... 1. 2. 1. 2. 2. 2. 1. ,. ,. cos. ,. ,. cos. B. éq 4.3.4-5. 4.4. Resolution of the modal problem under flow.

sním.i. oB]. L]. [La]. [M]. [Y].i. i. B]. L]. [La]. [M]. ... rinn sginerinn scinerind scine [.]. i. i. a cos. [B]. L]. [La]. [M].

sním.i. oB]. L]. [La]. [M]. [Y].i. i. B]. L]. [La]. [M]. ... rinn sginerinn scinerind scine [.]. i. i. a cos. [B]. L]. [La]. [M].

theta _{rm{c}}} = arctan frac{1}{{2sqrt 2 cos (60circ - varphi )}}{rm{ }}]. A proof of this formula is given here. ... B and A are initially at (cos φ', sin φ', 0) and (cos (φ' 60), sin (φ' 60), 0) respectively, while D is initially at. [

φ, bv = b cos θ , andgk = g sin θ cos φ with b and g the magnitudes of the Voigt andFaraday effects. ... These can be calculatedfrom the Fresnel equations [23],. tan ϕh = 2 cos ϑi.

U0 = (sin(z sin(t)) cos(y sin(t)),. sin(x sin(t)) cos(z sin(t)),. sin(y sin(t)) cos(x sin(t))). ... 0 1000 2000 3000t. 1010. 106. 102. E. KE. ME. (b) = 1.0.

We have. e 1 = cos φ e x sin φ e y,e 2 = sin φ e x cos φ e y, (11)e 3 = e z. ... R. )(ξ(0)b. d(i)e. )(9q23 3q. 21 3q. 22 3q3τ τ2 3q1τ cos(2φs) 3q2τ sin(2φs). ).

The duality statement Ka = Kb is perhaps geometrically obvious, since Ka and Kb arespherical cones with “center” ω and half-angles θa and θb, respectively, with cos θa = a,cos θb = ... Thetriangle inequality in spherical geometry gives γ α β.

z. (. µu. z. ). , 0 = p. y, 0 =. p. z ρg cos(α),. (2.6). 4 D. Pritchard, B. R. Duffy and S. ... The solution for p is. p = pa ρg cos(α)(h z) γ2h.

The fixed direction is given by the axis c. 5. Remark 2.6.b. ... ur. um. ul. ( )E. (a). (b). u'm. ur. um. ul( )H( )E.

cos is a special case of our reparametrised PER. 3 Model Search and EvaluationAs in Duvenaud et al. ... SE cos. Both demonstrate, using Bochner’s theorem(Bochner, 1959), that these kernels can approximate anystationary covariance function.

In this case, C = A cos(kL) 6= 0, B, and. ... values satisfy,. cos(k(2)n L) = 0 k(2)n =(. n 1. 2. ).

Rev. B 54, 6227-6242 (1996). 2. I. Avrutsky, Y. Zhao, and V. ... The lattice has primitive vectors a and b, where |a| = |b| and ab = |a|2 cos 60o.

of the α-effect, αv(B = 0) = χv = sin2 θ cos θ and Cα < 0(this determines the sign value of the hydrodynamic α ef-fect, see below in Sect. ... The value |Cα| (and |D|) chosen is perhaps largerthen expected because we use the profile χv = sin2 θ

j1 =12[sin(Φ) dΘ sin(Θ) cos(Θ) cos(Φ) dΦ],. j2 =12[cos(Φ) dΘ sin(Θ) cos(Θ) sin(Φ) dΦ],. ... with (recall that a2 a b2 = 0, see (3.4)). J′1 =12sin(Θ) cos(Θ) (a dΦ b dΦ),.

W(f,v)(a) = 0 iff BC1a(f) cos(θa) BC2a(f) sin(θa) = 0, f dom (Tmax). ... that. Sf = τf,. f dom (S) ={g dom (Tmax). BC1a(g) cos(θa) BC2a(g) sin(θa) = 0}.

bottom topography considered is described by:. b(x) =. . 0.25 cos(10π(x 1.5)) 1)) m if 1.4 m x 1.6 m,0 otherwise. ... 0. 0.5. 1. 1.5. x (m). (b. b U)/. b ref.