Search

2 Mar 2004: Why?) The solution is. T =. A0 2G(1 β)1r cos θ r < a,. ... The solution is. Φ(r, θ) ={ (. 1 3 ln(r/a))r cos θ/90 r < a.

23 Jan 2004: B(t) = v(t). [. ω1 sin ωt cos ωt. ]. [ cos ωt ω1 sin ωt ].(2.3). ... ω3,. b(2)2 (ω) =. 4(1 cos ω). ω2+. 8 sin ω.

25 Jun 2004: zd plane, then its wave functionis given by csx8 ,s8d where x8 = x cos a y sin a, s8=Îsy8 cos b z sin bd2+ sz cos b y8 sin bd2, ... and y8= y cos a x sin a.

17 Jun 2004: 2, for f (x) = cos 10x, g(x) = x,[a, b] = [0, 1] and 400 < ω < 500. ... Thus, consider Fig. 2.1, where we have plottedthe error for f (x) = cos 10x, g(x) = x, a = 0, b = 1.

8 Mar 2004: say. Then. Θ′′ = λΘ. = Θ =. A Bθ λ = 0A cos λθ B sin λθ λ 6= 0To obtain a sensible physical solution, replacing θ by θ 2π should give the same ... Θ =. A Bθ n = 0A cos nθ B sin nθ n 6= 0Returning to (2),.

8 Mar 2004: In vector notation,. this equation reads. (a. b)z = x |a|2|b|2y. ... Note that |a|2 = a. a and |b|2 are also scalars; hencea.b/|a| |b| = cos θ is a scalar, so that the angle between vectors is unaffected by a

7 Jan 2004: a aT b bT = (cos θ a sin θ b) (cos θ a sin θ b)T. ... cos θ b sin θ a) (cos θ b sin θ a)T , θ R, a, bRn̂, (5.4).