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Mathematical Tripos Part II E.J. HinchWAVES Lent 2013 Example ...
www.damtp.cam.ac.uk/user/hinch/teaching/D24b.pdf19 Jan 2013: Find the time-averaged energy flux vector 〈I〉 for (i) a plane harmonic S-wave with u =B cos(kx ωt), (ii) a plane harmonic P-wave with u = Ak̂ ... An SV-wave with displacement. u = B(cos θ, 0,sin θ)eik(x sin θz cos θ)iωt. -
Geometric transition in friction for flow over a bubble ...
www.damtp.cam.ac.uk/user/lauga/papers/25.pdf26 Jul 2013: cosh cos ,. it is found that. θ. (a) (b) (c). ... cos cos cosh cos. 4 sin2. cosh cos 2 sin sin. -
No many-scallop theorem: Collective locomotion of reciprocal swimmers …
www.damtp.cam.ac.uk/user/lauga/papers/23.pdf26 Jul 2013: b) Two dimers. We now consider the case of two dimersa and b. ... 482 2d3, 3a. V = ̄ab2 b1b1b2. ̄ba2 a1. a1a2 f a f b. -
Flapping motion and force generation in a viscoelastic fluid ...
www.damtp.cam.ac.uk/user/lauga/papers/24.pdf26 Jul 2013: evaluated at =. In Fourier notation and given that t= cos t, they become. ... 0. = 0. 2. Pressure and stress field. We have. ̃20 =. 2De1 De21 iDe1. B. 2 cos 2 sin 22, 43. as well as zero pressure p2 = 0, so that the average -
flm1100081a
www.damtp.cam.ac.uk/user/lauga/papers/50.pdf26 Jul 2013: With this in mind we let g2 = g1(z φ) with g1(z) = cos(z), andwe set equal for both sheets the bending stiffness B and the forcing amplitude A. ... B(576 B2. ) C, (3.7a)η2(z) = A. 12B [cos z cos(z φ)] [288 sin z (288 B2) sin(z φ)]B(576 B2). -
1B Methods 1 . 1B METHODS LECTURE NOTES Richard ...
www.damtp.cam.ac.uk/user/examples/B8La.pdf4 Oct 2013: cos A cos B =1. 2[cos(AB) cos(A B)]. sin A sin B =1. ... 2[cos(AB) cos(A B)]. sin A cos B =1. 2[sin(A B) sin(AB)]. -
Enhanced Diffusion by Reciprocal Swimming Eric Lauga Department of ...
www.damtp.cam.ac.uk/user/lauga/papers/52.pdf26 Jul 2013: 1(a). Our new result is illustrated in Fig. 1(c), where we showthe dynamics of swimmers undergoing reciprocal motionwith velocity Uswim UðtÞe and UðtÞ U cos!t withU 5 ... a) No swimming, (b) steady swimming at speed U 5 m=s, (c) reciprocalswimming at -
1B Methods 27 . 1B METHODS LECTURE NOTES Richard ...
www.damtp.cam.ac.uk/user/examples/B8Lb.pdf4 Oct 2013: TA sin θATA cos θA. µgδxT. (3). Now. TB sin θBTB cos θB. ... T(t) = cos jmnct and sin jmnct. Putting all this together i.e. -
doi:
www.damtp.cam.ac.uk/user/jneufeld/pubfiles/Hewitt-2013-1.pdf28 Nov 2013: X = 0 is given byF′ G = c0, (cos X σ0) G sin XF = 0, (4.4a,b). ... Θ = Ae(1κ2)τ cos κX Z, W = Ae(1κ2)τ cos κX, (5.1a,b)for any amplitude A. -
Inevitability of a magnetic �eld in the Sun'sradiative interiorD. …
www.damtp.cam.ac.uk/user/mem/oldftp/solar-nature.pdf19 Oct 2013: be similar to that of the spherical harmonicP4(cos ), and so we adopt the estimate L 4:5. ... Then equations(1) and (2) imply T=T r2c 2i =gL and juj 2g T=2N2T , where we have takensin cos 21=2. -
Optimal feeding is optimal swimming for all Péclet numbers ...
www.damtp.cam.ac.uk/user/lauga/papers/59.pdf26 Jul 2013: mal a or b at given Pe). Starting from a random initial condi-. ... For t 1, the swimming stroke,. b cos t b1 þ sin t bk; (44). -
§4 FLOWS WITH A FREE SURFACE Such flows are ...
www.damtp.cam.ac.uk/user/mem/FLUIDS-IB/waves.pdf19 Oct 2013: exponential counterpart, cos(µ) = 12 (e. ... Then φ̂ = φ̂(x, z) exp(kz) cos(kx),equivalent to a single pair of progressive deep-water waves travelling in the x directions. -
PHYSICAL REVIEW E 84, 061905 (2011) Energetics of synchronized ...
www.damtp.cam.ac.uk/user/lauga/papers/62.pdf26 Jul 2013: 3) leads to 2p = 0. A solutionof the harmonic equation for the pressure is, at the first order inkb, p = p1(r,θ) (A cos s B sin s) with s = ... xi = x0 b cos β sin (s φ) , (34)yi = y0 b sin β sin (s φ). -
§3 IRROTATIONAL FLOWS, aka POTENTIAL FLOWS Irrotational flows are ...
www.damtp.cam.ac.uk/user/mem/FLUIDS-IB/irrot-rot.pdf19 Oct 2013: expected. (ii) all A’s, B’s zero except A1:. φ = A1r cos θ = A1z , u = φ = A1ez. ... z. (iii) all A’s, B’s zero except B1:. φ =B1 cos θ. -
PHYSICAL REVIEW E 87, 023015 (2013) Interface pinning of ...
www.damtp.cam.ac.uk/user/jneufeld/pubfiles/Zhao-2013.pdf4 Nov 2013: r1 = [2 cos(φ1)]cos(φ1 θ ). d. 2, (3). r2 = [2. ... 2 cos(φ2)]cos(φ2 θ ). d. 2. (4). In drainage, θ = θr and the drainage capillary entrypressure corresponds to the minimum radius of curvature r1:rdr = minφ1 r1(φ1; θr ). -
1B Methods 62 . 1B METHODS LECTURE NOTES Richard ...
www.damtp.cam.ac.uk/user/examples/B8Lc.pdf4 Oct 2013: B(cos(1 ξ)) A cos ξ = 1. Solving these two equations for A and B gives the Green’s function to be:. ... Then. I. λ=. 0. cos(λx)eαxdx = <(. 0. e(αλi)xdx. ),. = <[e(αλi)x. -
Passive hydrodynamic synchronization of two-dimensional swimming…
www.damtp.cam.ac.uk/user/lauga/papers/47.pdf26 Jul 2013: uy=y1 = 1 ṠR cos y=y1 , 11a. vy=y1 = ṠR sin y=y1 , 11b. ... uy=y2 = 1 ṠR cos y=y2 U , 11c. vy=y2 = ṠR sin y=y2. -
PHYSICS OF FLUIDS 25, 071904 (2013) The wobbling-to-swimming…
www.damtp.cam.ac.uk/user/lauga/papers/81.pdf26 Jul 2013: B]lab = B0[cos(ωt ), si n(ωt ), 0]T. (2). Experimentally this magnetic field provides an external torque to the head of the artificial flagellumbut no external force. ... ξ̄‖ =ξ‖. µ= 2π. ln(2 cos θ/γ ) 1/2,. ξ̄ =ξ. -
The friction of a mesh-like super-hydrophobic surfaceAnthony M. J. ...
www.damtp.cam.ac.uk/user/lauga/papers/33.pdf26 Jul 2013: 4 m1=1. m2=1. 1. m12 m221 m12. 2m12 m2. 2cos 2 b m1x cos 2 b m2y , 18from which we note that large contributions to Eqs. ... cos m2w W. m1=1. 1m Cm 12m1 12 ln S sdwds , 20b. -
flm469.dvi
www.damtp.cam.ac.uk/user/lauga/papers/4.pdf26 Jul 2013: a) The no-shear regions are transverse to the flow direction. (b) Theno-shear regions are parallel to the flow direction. ... Thesolution to this problem was derived by conformal mapping in Philip (1972a) and isrecalled in Appendix B.
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