Search
Search Funnelback University
- Refined by:
- Date: 2013
11 -
20 of
37
search results for `B b cos` |u:www.damtp.cam.ac.uk
Fully-matching results
-
Optimal feeding is optimal swimming for all Péclet numbers ...
www.damtp.cam.ac.uk/user/lauga/papers/59.pdf26 Jul 2013: mal a or b at given Pe). Starting from a random initial condi-. ... For t 1, the swimming stroke,. b cos t b1 þ sin t bk; (44). -
§4 FLOWS WITH A FREE SURFACE Such flows are ...
www.damtp.cam.ac.uk/user/mem/FLUIDS-IB/waves.pdf19 Oct 2013: exponential counterpart, cos(µ) = 12 (e. ... Then φ̂ = φ̂(x, z) exp(kz) cos(kx),equivalent to a single pair of progressive deep-water waves travelling in the x directions. -
PHYSICAL REVIEW E 84, 061905 (2011) Energetics of synchronized ...
www.damtp.cam.ac.uk/user/lauga/papers/62.pdf26 Jul 2013: 3) leads to 2p = 0. A solutionof the harmonic equation for the pressure is, at the first order inkb, p = p1(r,θ) (A cos s B sin s) with s = ... xi = x0 b cos β sin (s φ) , (34)yi = y0 b sin β sin (s φ). -
§3 IRROTATIONAL FLOWS, aka POTENTIAL FLOWS Irrotational flows are ...
www.damtp.cam.ac.uk/user/mem/FLUIDS-IB/irrot-rot.pdf19 Oct 2013: expected. (ii) all A’s, B’s zero except A1:. φ = A1r cos θ = A1z , u = φ = A1ez. ... z. (iii) all A’s, B’s zero except B1:. φ =B1 cos θ. -
1B Methods 62 . 1B METHODS LECTURE NOTES Richard ...
www.damtp.cam.ac.uk/user/examples/B8Lc.pdf4 Oct 2013: B(cos(1 ξ)) A cos ξ = 1. Solving these two equations for A and B gives the Green’s function to be:. ... Then. I. λ=. 0. cos(λx)eαxdx = <(. 0. e(αλi)xdx. ),. = <[e(αλi)x. -
PHYSICAL REVIEW E 87, 023015 (2013) Interface pinning of ...
www.damtp.cam.ac.uk/user/jneufeld/pubfiles/Zhao-2013.pdf4 Nov 2013: r1 = [2 cos(φ1)]cos(φ1 θ ). d. 2, (3). r2 = [2. ... 2 cos(φ2)]cos(φ2 θ ). d. 2. (4). In drainage, θ = θr and the drainage capillary entrypressure corresponds to the minimum radius of curvature r1:rdr = minφ1 r1(φ1; θr ). -
Passive hydrodynamic synchronization of two-dimensional swimming…
www.damtp.cam.ac.uk/user/lauga/papers/47.pdf26 Jul 2013: uy=y1 = 1 ṠR cos y=y1 , 11a. vy=y1 = ṠR sin y=y1 , 11b. ... uy=y2 = 1 ṠR cos y=y2 U , 11c. vy=y2 = ṠR sin y=y2. -
PHYSICS OF FLUIDS 25, 071904 (2013) The wobbling-to-swimming…
www.damtp.cam.ac.uk/user/lauga/papers/81.pdf26 Jul 2013: B]lab = B0[cos(ωt ), si n(ωt ), 0]T. (2). Experimentally this magnetic field provides an external torque to the head of the artificial flagellumbut no external force. ... ξ̄‖ =ξ‖. µ= 2π. ln(2 cos θ/γ ) 1/2,. ξ̄ =ξ. -
Inevitability of a magnetic �eld in the Sun'sradiative interiorD. …
www.damtp.cam.ac.uk/user/mem/oldftp/solar-nature.pdf19 Oct 2013: be similar to that of the spherical harmonicP4(cos ), and so we adopt the estimate L 4:5. ... Then equations(1) and (2) imply T=T r2c 2i =gL and juj 2g T=2N2T , where we have takensin cos 21=2. -
flm469.dvi
www.damtp.cam.ac.uk/user/lauga/papers/4.pdf26 Jul 2013: a) The no-shear regions are transverse to the flow direction. (b) Theno-shear regions are parallel to the flow direction. ... Thesolution to this problem was derived by conformal mapping in Philip (1972a) and isrecalled in Appendix B.
Search history
Recently clicked results
Recently clicked results
Your click history is empty.
Recent searches
Recent searches
Your search history is empty.