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17 Jan 2013: Experimental Consequences of the S-wave cos(k. x. ) cos(k. y. ) Superconductivity in the Iron-Pnictides. ... B 78, 144514 (2008). Stability and pairing in quasi-one-dimensional Bose-Fermi mixtures.

5 Mar 2012: βH′[φ<] = Z0> βH0[φ<] d2x g〈cos[λ(φ<(x) φ>(x))]〉> O(g2). (b) Working to first order in g, show that, under the RG transformation, theparameters obey the ... βH′[φ′] =. d2q. (2π)2K(b). 2q′2|φ(q)|2. d2x′ g(b) cos [λ(b)φ′(x′)].

24 Aug 2020: the gauge field as A = 2ih̄〈χ |χ 〉 = h̄ cos θ φ̂/ρ. ... Finally, we compare thepredictions for the gauge field realized by the proposed lasersetup, A = 2h̄ cos θ φ̂/ρ [Figs.

8 Jan 2024: L =1. 2m. [a2η̇2 2al sin(η θ)η̇θ̇ l2θ̇2. ] mg(l cos θ a sin η) 1. ... 2b2k(sin η sin η0)2. [6]. (b) Find the Euler-Lagrange equations of motion.

24 Aug 2020: G. J. CONDUIT AND P. D. HAYNES PHYSICAL REVIEW B 78, 195310 2008. ... DIFFUSION MONTE CARLO STUDY OF A VALLEY-… PHYSICAL REVIEW B 78, 195310 2008.

10 Oct 2012: Ĥ = JN S2 B.Z.Xk! ka†kak O(S0) (2.16). where! k = 2JS(1 cos k) = 4JS sin2(k/2) represents the dispersion relation of the spinexcitations. ... aka†k. O(S0),. where k = cos k.Quadratic in the bosonic operators, the Hamiltonian can be again

23 Dec 2020: Online version in colour.). (b). (c). – a2a2 a. x. –1.0–0.5. ... c (x,. y,x). Figure6. (a)Three-,(b)two-and(c)one-dimensionalplotsoftheoscillatorypartoftheelectronclouddensity,ρoscE (x, y, z) =[cos(kx) cos(ky) cos(kz)]/3 with k = 2π/a, for the

21 Oct 2009: B = B0êz B1(êx cos(ωt) êy sin(ωt)). Paramagnetic resonance. This result shows that spin precessionfrequency is independent of spin orientation. ... B = B0êz B1(êx cos(ωt) êy sin(ωt)). Paramagnetic resonance. B = B0êz B1(êx cos(ωt)

4 Apr 2010: r(t) = A cos(ωt) B sin(ωt). Applying the boundary conditions r(0) = 0 and r(t̄) = r̄ we find A = 0 andB = r̄/ sin(ωt̄),. ... cos qd D q2. 2+. Inverting and applying the inverse Fourier transform, we obtain.

21 Oct 2009: i. 2γσ Bt. ]. Therefore, for initial spin configuration,. (αβ. )=. (eiϕ/2 cos(θ/2)eiϕ/2 sin(θ/2). ). With B = Bêz , Û(t) = exp[ i2 γBtσz ], |ψ(t)〉 = Û(t)| ... B = B0êz B1(êx cos(ωt) êy sin(ωt)). Paramagnetic resonance. B =

7 Jan 2019: L =1. 2m(. ρ̇2 ρ2θ̇2). 12kρ2 q. (. Eρ cos θ B. ... A =B. 2. (. ρ sin θ, ρ cos θ, 0).

9 Jun 2004: vxωc. (. ωc =eB. m. ). (X,Y). (x,y). Ẋ =Ey(r,t). BẎ =. Ex(r,t). B. SAW potential: E(r,t) = Eωq cos[qx ωt]̂x. Perturbation theory:. ... ignoring disorder:. x0(t) = X0 Rc cos (ωct ψ) , y0(t) = Y0 Rc sin (ωct ψ).

7 Jan 2019: L =1. 2. [η̇2 2η̇θ̇ cos θ θ̇2. ]g. cos θ 1. ... 2. k. mη2 ,. up to a multiplicative constant. [10]. (b) Find the equations of motion for this system.

24 Oct 2022: x(t) = A cos(ω0t) B sin(ω0t). (11). This form also has two constants,A andB, which we can use to specify the motion of the systemat t = 0. ... which matches the second form of the solution provided. A = a0 cos(φ) B = a0 sin(φ).

7 Jan 2019: b) The canonical momentum conjugate to x is. px =L. ẋ= (m1 m2)ẋ m2lφ̇ cos φ. ... circular motion around the z axis with constantangular velocity. In terms of the z coordinate, the particle undergoes simpleharmonic motion, z(t) = a sin κt b cos κt

8 Jan 2024: x = a cos(η) l sin(θ), z = l cos(θ) a sin(η). ... mg(l cos(θ) a sin(η)) 12b2k(sin(η) sin(η0))2. A. 3. (b) Find the Euler-Lagrange equations of motion.

21 Jan 2018: L =1. 2. [η̇2 2η̇θ̇ cos θ θ̇2. ]g. cos θ 1. ... 2. k. mη2 ,. up to a multiplicative constant. [10]. (b) Find the equations of motion for this system.

10 Nov 2013: 2t cos ka)c†kσckσ. /a. (k). /a k-. B.Z. As expected, as k 0, spectrum becomes free electron-like:k 2t t(ka)2 (with m = 2/2a2t). ... k. cos k a†kak. Ĥ = JNS2 B.Z.k. ωka†kak O(S.

7 Jan 2019: 6]An electromagnetic wave is represented by the 4-vector potential. Aµ = (0, A cos(kz ωt), A sin(kz ωt), 0). ... a) Evaluate the electric and magnetic fields. [6]. (b) Evaluate the Lagrangian density.

7 Jan 2019: x/a = θ sin φ (θ φ) cos φ ,y/a = 1 cos φ (θ φ) sin φ. ... A. (TURN OVER for continuation of question 4. 4. (d) By considering a wave solution of the form ϕ = C cos(kxωt) for auniform rod, find the dispersion relation and the

7 Jan 2019: E m2gl cos φ. [9]. 2 A harmonic oscillator is weakly perturbed by a cubic potential λx3 so thatits Hamiltonian has the form. ... 19]. (b) Find the temperature T (x, t) of the system if s(x, t) = cos(px)δ(t t0)and T (x, t < t0) = 0, for the two cases

7 Jan 2019: m. (a, ,b ). z. M. (r, ,z). B B. (a) Show that, up to irrelevant constants and ignoring gravity, the Lagrangian forthe system is: [6]. ... 2k(r2 2ar cos(θ θB) (z bθB)2. ). A. (TURN OVER for continuation of question 1.

18 Jan 2014: L =1. 2m(. ρ̇2 ρ2θ̇2). 12kρ2 q. (. Eρ cos θ B. ... A =B. 2. (. ρ sin θ, ρ cos θ, 0).

7 Jan 2019: The Lagrangian is. L = T V = m2. (a2ω2 l2θ̇2 2alωθ̇ cos(ωt θ). ) ... y = A cos(ω0t δ) Et. B(16). The path is a helix (free motion in z) that drifts at a rate E/B in the ydirection.

20 Jan 2016: m. (a, ,b ). z. M. (r, ,z). B B. (a) Show that, up to irrelevant constants and ignoring gravity, the Lagrangian forthe system is: [6]. ... 2k(r2 2ar cos(θ θB) (z bθB)2. ). A. (TURN OVER for continuation of question 1.

7 Jan 2019: L =1. 2m[ȧ2x ȧ. 2y l. 2θ̇2 2lθ̇(ȧx cos θ ȧy sin θ)] mg(ay l cos θ). ... lcos(θ1) cos(ωt),. A. (TURN OVER for continuation of question 1. 2.

6 Aug 2013: b) The canonical momentum conjugate to x is. px =L. ẋ= (m1 m2)ẋ m2lφ̇ cos φ. ... circular motion around the z axis with constantangular velocity. In terms of the z coordinate, the particle undergoes simpleharmonic motion, z(t) = a sin κt b cos κt

24 Aug 2020: IV B we studythe temperature-dependent current in a Josephson junction.In Sec. ... no additional resistance.The current J (T ) = JJ(T ) cos(φL φR) is maintained by the.

14 Jan 2009: 6]An electromagnetic wave is represented by the 4-vector potential. Aµ = (0, A cos(kz ωt), A sin(kz ωt), 0). ... a) Evaluate the electric and magnetic fields. [6]. (b) Evaluate the Lagrangian density.

25 Jan 2010: x/a = θ sin φ (θ φ) cos φ ,y/a = 1 cos φ (θ φ) sin φ. ... A. (TURN OVER for continuation of question 4. 4. (d) By considering a wave solution of the form ϕ = C cos(kxωt) for auniform rod, find the dispersion relation and the

6 Aug 2013: E m2gl cos φ. [9]. 2 A harmonic oscillator is weakly perturbed by a cubic potential λx3 so thatits Hamiltonian has the form. ... 19]. (b) Find the temperature T (x, t) of the system if s(x, t) = cos(px)δ(t t0)and T (x, t < t0) = 0, for the two cases

20 Jan 2009: a) The electric field is. E = Ȧ = Aω ( sin(kz ωt), cos(kz ωt), 0). ... The magnetic field is. B = A = Ak ( cos(kz ωt), sin(kz ωt), 0).

6 Nov 2021: 0 = ma22(sin θ cos θ sin φ cos φ) mga(sin θ sin φ). ... 1. 2π. g/a cos θ0 2 cos 2θ0,. and find the other normal frequency.

15 Jan 2003: The Lagrangian is. L = T V = m2. (a2ω2 l2θ̇2 2alωθ̇ cos(ωt θ). ) ... y = A cos(ω0t δ) Et. B(16). The path is a helix (free motion in z) that drifts at a rate E/B in the ydirection.

18 Jan 2015: L =1. 2m[ȧ2x ȧ. 2y l. 2θ̇2 2lθ̇(ȧx cos θ ȧy sin θ)] mg(ay l cos θ). ... lcos(θ1) cos(ωt),. A. (TURN OVER for continuation of question 1. 2.

17 Jul 2009: 2D d = d(sin θ, 0, cos θ) k kx [Bruun & Taylor, PRL 101, 245301 (2008)]. ... d|〉 = deff (cos ωt, sin ωt, 0)ωt r. θ. V0(r, θ; t) =d2effr3. [.

8 Oct 2009: B = B0ẑ B1(êx cos(ωt) êy sin(ωt)). The effective magnetic field in the frame rotating with the same frequency ωas the small added field is then given by. ... The EM wave has (angular) frequency ω,. Ĥ =gp2. µN Bzσz Bx cos(ωt)σx =gp2.

19 Jan 2015: 2θ̇2 2lθ̇(ȧx cos(θ) ȧy sin(θ)) mg(ay l cos(θ)). (b) We have. ... Veff(θ) = ml. (. g sin(θ) 12. a2. lω2 sin(θ) cos(θ). ).

2 Aug 2018: Chern number can be obtained by tomography of Bloch statesTwo-band model: |uk (t)〉 = sin(θk/2)|A, k〉 cos(θk/2) exp(iφk )|B, k〉. ... N. Fläschner, B. S. Rem, M. Tarnowski,. D. Vogel, D.-S. Lühmann, K.

22 Jan 2024: H, 〉 =(. cos (θ/2) eiφ/2. sin (θ/2) eiφ/2. ). (1.80). ... We first fix an explicit form for the triad. a = (cos θ cos φ, cos θ sin φ,sin θ)b = (sin φ, cos φ, 0)n = (sin θ cos φ,

24 Jan 2011: 2. (2P1 cos(ωt ϕ) Q2. )py =. α. 2. (2P1 sin(ωt ϕ) P2. ... µ and WµWµ. The coefficients are. m2. λ[e cos α e′ sin α].

24 Oct 2022: 2g cos(θ1) 2lθ̇21 lθ̇. 22 cos(θ1 θ2). ). l(cos(2(θ1 θ2)) 3). ... The Lagrangian is thus:. L(θ, θ̇) = T V = 12ml2θ̇2 mgl cos(θ).

31 Aug 2016: Ek = 2J cos(k θ) (k qAx )2. 2m. [can be removed by a gauge transformation]. ... b) λ0. Ek = 2λ |α|cos (k θ) α = |α|eiθ =λK.

28 Oct 2009: Ĥ(1) = eEr cos θ. To answer this question, we must turn to degenerate perturbationtheory. ... 1. 32πa30. )1/2er/2a0. (. 2 ra0). ra0. cos θra0. eiφ sin θ.

12 Oct 2009: In central well region, general solution of the form. ψ2(x) = A cos(kx) or B sin(kx),! ... leads to the condition,. k [An1 cos(ka) Bn1 sin(ka) An] =2maV0!

7 Jan 2019: a) The electric field is. E = Ȧ = Aω ( sin(kz ωt), cos(kz ωt), 0). ... The magnetic field is. B = A = Ak ( cos(kz ωt), sin(kz ωt), 0).

7 Jan 2019: x = η sin θ y = cos θ. Correspondingly, the kinetic energy is given by [3]. ... 1. 2m2. [η̇2 θ̇2 2θ̇η̇ cos θ. ]and the potential energy by [3].

7 Jan 2019: 2θ̇2 2lθ̇(ȧx cos(θ) ȧy sin(θ)) mg(ay l cos(θ)). (b) We have. ... Veff(θ) = ml. (. g sin(θ) 12. a2. lω2 sin(θ) cos(θ). ).

21 Jan 2018: x = η sin θ y = cos θ. Correspondingly, the kinetic energy is given by [3]. ... 1. 2m2. [η̇2 θ̇2 2θ̇η̇ cos θ. ]and the potential energy by [3].

8 Oct 2009: t =2k1k2eik1a. 2k1k2 cos(k2a) i(k21 k22) sin(k2a),. Advanced Quantum Physics. 2.1. ... the form. ψ(a < x < a) = A cos(kx) B sin(kx) ,. where k =. 2m(EV0)!2. Once again we have four equations in four unknowns.