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17 Jun 2019: Prove the Pythagorean theorem for spherical geometry in the form. cos c = cos a cos b. ... E = (E0 cos(kz ωt), 0, 0) B = (0,B0 cos(kz ωt), 0),.

30 Aug 2019: χ =(A cos αr. B sin αrr. cr2). sin2 θ. Find conditions on A,B,C and α for which B = 0 on the sphere r = a, and givean expression for ... πc(τ) sin 2πz,. χ =1k. [πd(τ). ( 8p. )1/2sin kx cos πz e(τ) sin 2kx. ],.

17 Jun 2019: φ(r,θ) = A B log r. n=1. [rn(An cos nθ Bn sin nθ) rn(Cn cos nθ Dn sin nθ)]. ... where An, Bn, Cn and Dn are constants. [10]. Obtain the solution for φ(r,θ) given the boundary conditions φ(a,θ) = U andφ(b,θ) = V cos θ.

17 Jun 2019: σ(u,v) = ((a b cos u) cos v, (a b cos u) sin v,b sin u),. ... ψ(x) =15a. cos(πx. 2a. ). 25a. sin(πxa. ),. in the region a x a, and zero otherwise.

9 Nov 2023:  , G =. y cos(xy) by (b c)z. x cos(xy) bx bz(c b)x by. ... a) Find the general solution of the differential equation. d2y. dx2+ y = cos(kx) ,. where k is a positive integer. [10]. (b) (i) Rewrite the set of simultaneous differential equations

17 Jun 2019: sationσ(u, v) =. ((a b cos u) cos v, (a b cos u) sin v, b sin u. ),. ... 2π. 0. sin2 θdθ. a b cos θ=. 2π. b2. [a.

17 Jun 2019: 1]. B C. A. D. 2. 5. Solve for x in the interval 0 6 x 6 π: cos 2x = sinx. ... 1]. Natural Sciences IA, Paper 1. 5. SECTION B. 11Z. (a) Use De Moivre’s theorem to express 8 cos(6θ) 15 sin(4θ) sin(2θ) in terms of cos θand

17 Jun 2019: u(x,y,0) =. m=1. n=1. Amne β. 2x sin(mπx) cos. (. 2n12 πy. ). ,. ... exp(M) =. . . . . cosha sinha 0 0sinha cosh a 0 00 0 cos b sinb0 0 sinb cos b.

17 Jun 2019: Φ(r, θ) =. n=0. (Anr. n Bnrn1)Pn(cos θ). for constants An, Bn. ... The temperatureon the boundaries of the shell is. T (a, θ) = T0 T1 cos θ, T (b, θ) = T2 T3 cos θ ,. for constants T0, T1, T2, T3. Determine the

30 Aug 2019: X(θ) = b(cos θ, sin θ, θ tan φ), 0 6 θ 6 L cos φ/b, (). where φ is the pitch of the helix (i.e. the constant angle ... between dX/dθ and the xy-plane)and L cos φ b.